We need to find a polynomial function f(x) with degree 3 and zeros 2 and 2i, such that:

Since 2i is a zero, -2i is also a zero of this function. Thus, we have:

where a is a constant.
Expanding the expression on the right side, we obtain:

Now, using f(-1) = 30, we obtain:

Therefore, the function is:
Answer
There is no solution
I put it in an online calculator and it said that as well
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