3 years ago

Common factor: 3x^2y^2z^2+5xyz—8x^2

Mathematics

1 answer:

Elza [17]3 years ago

3 0

Answer:

Step-by-step explanation:

Find the prime factors of each term in order to find the greatest common factor (GCF).

You might be interested in

For a one-tailed test with a = .05 and a sample of n = 9, the critical value for the t statistic is t = 1.860.

ahrayia [7]

I think its B. False if im wrong sorry hope this helped tho :p

6 0

3 years ago

What is the simplified form of the following expression?

kogti [31]

Answer:

$\sqrt{3}$

Step-by-step explanation:

We will be using 2 properties of radicals in this simplification (outlined below).

$\sqrt{a*b}=\sqrt{a}* \sqrt{b}$
$\sqrt{a}*\sqrt{a}=a$

<em>Let's simplify this:</em>

$2\sqrt{27} +\sqrt{12} -3\sqrt{3}-2\sqrt{12}\\ =2\sqrt{9*3}+\sqrt{4*3} -3\sqrt{3}-2\sqrt{4*3} \\=2\sqrt{9} \sqrt{3} +\sqrt{4} \sqrt{3}-3\sqrt{3}-2\sqrt{4} \sqrt{3} \\=2(3)\sqrt{3}+(2)\sqrt{3} -3\sqrt{3}-2(2)\sqrt{3} \\ =6\sqrt{3} +2\sqrt{3}-3\sqrt{3}-4\sqrt{3} \\=\sqrt{3}$

First answer choice is right.

5 0

3 years ago

Determine the number of centimeters in 2 inches.

Paul [167]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A seasonal index for a monthly series is about to be calculated on the basis of three years’ accumulation of data. The three pre

yarga [219]

Answer:

0.684

Step-by-step explanation:

According to the scenario, computation of the given data are as follows

Seasonal index = Average value for July ÷ Average over all months

Where, Average value for July = ( 110 + 150 + 130 ) ÷ 3

= 390 ÷ 3 = 130

And, average over all months = 190

So by putting the value in the formula, we get

Seasonal index = 130 ÷ 190

= 0.684211 or 0.684

Hence, approximate seasonal index for July is 0.684.

6 0

3 years ago

Whats the answer and work for 7x+8(x+1/4)=3(6x-9)-8 ?

Marat540 [252]

Answer:

=37

Step-by-step explanation:

3 0

2 years ago