Sec theta = 1/cos theta = 1/0.5 = 2
Option D is the correct answer.
Answer:
A) 1/45
B) 1/60
Step-by-step explanation:
<u>Part A</u>
The actual car has a length to width ratio of ...
length/width = (570 cm)/(180 cm) = 57/18 = 3 1/6
The rectangle on the screen has a length to width ratio of ...
length/width = (13 cm)/(4 cm) = 3 1/4
Relative to its width, the screen rectangle is longer than necessary for a model of the car. So, the scale factor will be determined by the width of the car relative to the width of the screen model.
For a model width of 4 cm, the scale factor is ...
model/life-size = (4 cm)/(180 cm) = 1/45
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<u>Part B</u>
For a model width of 3 cm, the scale factor is ...
model/life-size = (3 cm)/(180 cm) = 1/60
Answer:0.0081 or 0.81%
Step-by-step explanation:
The required probability is P(3,5,0.1)= C5 3 * p^3*q^2, where
C5 3= 5!/3/2=4*5/2=10
p is the probability that one randomly selected calculator is defective= 10%=0.1
q is the probability that one randomly selected calculator is non-defective.
q=1-p=1-0.1=0.9
So P(3,5,0.1)= 10*0.1^3*0.9^2=0.01*0.81=0.0081
1/2, because 3/10 + 1/5 = 5/10. that means that the other part of 1 is 5/10 or 1/2
It is the third equation: −512⋅(65⋅13)⋅92=(−512⋅65)⋅(13⋅92)
Associative property means one can group the individual operations arbitrarily without changing the result.
