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2 years ago

What mistake happens in the promblem 90-47=43

Mathematics

2 answers:

Natalka [10]2 years ago

3 0

Answer:

the only mistake i see here is your spelling error.

Step-by-step explanation:

RoseWind [281]2 years ago

3 0

Answer:

90 minus 47 is 43

Step-by-step explanation:

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Christopher bought a new watch at the store one day we're having a 20% off sale if the regular price of the watch was 48 how muc

Diano4ka-milaya [45]

Answer:

$38.40

Step-by-step explanation:

to get your total you multiply

48 x 20% =9.60

then you subtract 48.00 - 9.60 = $38.40

8 0

3 years ago

Somebody explain pls!!!!!

Furkat [3]

Step-by-step explanation:

Using log properties

$log_{7}(rz {}^{12} )$

$log_{7}(r) + log_{7}(z {}^{12} )$

Then

$log_{7}(r) + 12 log_{7}(z)$

Plug in the knowns

$- 7.87 + 12( - 12.59)$

$- 158.95$

5 0

1 year ago

Find derivative problem Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$

Therefore:

$\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]$

By simplification:

$\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17$

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

5 0

3 years ago

Help me wiht this plssss

yulyashka [42]

Answer:

well you find. out how many all of them measure. and add them and then that answer multiply of the main number

Step-by-step explanation:

first add up all of the lengths and then find that answer multiply it to the main number and then you will get your anwer it's a 2 step problem

7 0

2 years ago

Solve the equation ƒ - (-4) = 12. ƒ = -8 ƒ = 16 ƒ = 8 ƒ = -9

Anarel [89]

Step-by-step explanation:

-8 - -4= -8+4=-4

16- -4=20

8- -4=12

-9--4=-5

3 0

2 years ago

Read 2 more answers