Your English teacher has decided to randomly assign poems for the class to read. The syllabus includes four poems by Shakespeare
, five poems by Coleridge, two poems by Tennyson, and two poems by Lord Byron. What is the probability that you will be assigned a poem by Shakespeare, and then a poem by Tennyson?
The probability of event A and B to both occur is denoted as P(A ∩ B) = P(A) P(B|A). It is the probability that Event A occurs times the probability that Event B occurs, given that Event A has occurred.
So, to find the probability that you will be assigned a poem by Shakespeare and by Tennyson, let Event A = the event that a Shakespeare poem will be assigned to you; and let Event B = the event that the second poem that will be assigned to you will be by Tennyson.
At first, there are a total of 13 poems that would be randomly assigned in your class. There are 4 poems by Shakespeare, thus P(A) is 4/13. After the first selection, there would be 13 poems left. Therefore, P(B|A) = 2/12 Based on the rule of multiplication, P(A ∩ B) = P(A) P(B|A)P(A ∩ B) = 4/13 * 2/12 P(A ∩ B) = 8/156 P(A ∩ B) = 2/39
The probability that you will be assigned a poem by Shakespeare, then a poem by Tennyson is 2/39 or 5.13%.
I think that it's B, y = -x - 7 because first you'd subtract y to get it on the other side then add x and then you'd need to make the y positive so you would divide x + 7 by -1 and that would make it y = -x - 7.
Answer:No solution Explanation: There is no solution because x was eliminated in the last step of solving for x. Since we were left with x not being available to equal three, it shows it’s a no solution problem. Hope this helped!
