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3 years ago

What’s the answer ??

Mathematics

1 answer:

zhuklara [117]3 years ago

3 0

So, first you do 4x+54 is greater than or equal to 70 first you subtract 54 from both sides and get -16 and then you divide by 4 by both sides and get x=-4 I hope this helps :).

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Please help asap. Thank you so much! Question 1/7

solniwko [45]

What class is for ? If you tell me I could take out my notes

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2 years ago

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PLEASE HELP ME FOR BRAINLIEST ANSWER An architect designs a rectangular flower garden such that the width is exactly two-thirds

Oksanka [162]

Answer:

Length: 84 ft

Width: 56 ft

Step-by-step explanation:

Let's define some variables first.

Call the length l and width w.

We know that w = 2/3l. Therefore, we can express w in terms of l with this expression.

Now, let's set up an equation. The flower garden is rectangular, and 280 feet of fencing are used to enclose the garden. This represents perimeter.

Remember the formula for perimeter of a rectangle: 2l + 2w

Let's substitute 2/3l for w:

2l + 2*2/3l = P

2l + 4/3l = 280

2 4/3l = 280

10/3l = 280

l = 84

Now, we know that the length is equal to 84 feet. We can multiply 84 feet by 2/3 to find the width.

84*2/3 = 56

Length: 84 ft

Width: 56 ft

Let's plug these values into the formula and see if they give us the correct perimeter:

2l + 2w = P

2*84 + 2*56 = P

168 + 112

= 280 feet

These are the correct dimensions!

Hope this helps! You can reach out to me if you have further questions or concerns! :)

6 0

2 years ago

Helppp me thank youu!<br>BRAINIEST GIVEN!!

dimaraw [331]

Answer:

Step-by-step explanation:

2 is the square root of 4 since 2×2=4

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1 year ago

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PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS

Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

$a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\$

With respect to reference angle A, we have:

opposite side = a = 4
adjacent side = b = $\sqrt{33}$
hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\$

Then cosine which is adjacent over hypotenuse

$\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\$

Tangent is the ratio of opposite over adjacent

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\$

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

cosecant, abbreviated as csc, is the reciprocal of sine
secant, abbreviated as sec, is the reciprocal of cosine
cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

$\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{ ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

------------------------------------------------------

Summary:

The missing side is $b = \sqrt{33}$

The 6 trig functions have these results

$\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

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Which pair is a base and corresponding height for the triangle?

Vikki [24]

<span> B. b = 20 units and h = 16 units </span>

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