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Ierofanga [76]
2 years ago
11

Whats this answer please ?

Mathematics
1 answer:
bagirrra123 [75]2 years ago
5 0

Answer:

  • area of rectangle: 48 cm²
  • area of triangle: 18 cm²
  • shaded area: 30 cm²

Step-by-step explanation:

The area of a rectangle is given by the product of its length and width.

... A = LW

For your rectangle, the overall area is ...

... A = (12 cm)(4 cm) = 48 cm² . . . . rectangle area

___

The area of a triangle is half the product of its base and height. Your triangle is shown with a base of 9 cm, and its height is the height of the rectangle, 4 cm. The triangle area is ...

... A = (1/2)bh

... A = (1/2)(9 cm)(4 cm) = 18 cm² . . . . triangle area

___

The shaded area of the figure is the difference between the rectangle area and the triangle area. (The triangle is fully included in the rectangle, but is not shaded.) That difference is ...

... shaded area = rectangle area - triangle area

... shaded area = 48 cm² - 18 cm² = 30 cm² . . . . shaded area

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A circle has a radius of 6 in. The circumscribed equilateral triangle will have an area of:
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216

Step-by-step explanation:

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A new app charges an annual fee plus an additional fee per new game downloaded. The table shows the linear relationship between
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The correct answer is below:

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2 years ago
Find the equation of the circle in standard form for the given center (h, k) and radius r: (h, k) = (0, 0), r = 4
Ad libitum [116K]

Answer:

x^2+y^2=16

Step-by-step explanation:

The equation of a circle with center (h,k) and radius r is given by the formula;

(x-h)^2+(y-k)^2=r^2

Given (h,k)=(0,0) and r=4, we substitute the values to obtain;

(x-0)^2+(y-0)^2=4^2

The required equation is

x^2+y^2=16

8 0
3 years ago
Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 1
Yuri [45]

Answer:

90% confidence interval for the population mean test score is [95.40 , 106.59]

Step-by-step explanation:

We are given that the population mean score for mathematics test is 115. It is known that the population standard deviation of test scores is 17.

Also, a random sample of 25 students take the exam. The mean score for this group is 101.

The, pivotal quantity for 90% confidence interval for the population mean test score is given by;

        P.Q. = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean = 101

              \sigma = population standard deviation

              n = sample size = 25

So, 90% confidence interval for the population mean test score, \mu is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.6449) = 0.90

P(-1.6449 * \frac{\sigma}{\sqrt{n} } < {Xbar-\mu} < 1.6449 * \frac{\sigma}{\sqrt{n} } ) = 0.90

P(X bar - 1.6449 * \frac{\sigma}{\sqrt{n} } < \mu < X bar + 1.6449 * \frac{\sigma}{\sqrt{n} } ) = 0.90

90% confidence interval for \mu = [ X bar - 1.6449 * \frac{\sigma}{\sqrt{n} } , X bar + 1.6449 * \frac{\sigma}{\sqrt{n} } ]

                                                  = [ 101 - 1.6449 * \frac{17}{\sqrt{25} } , 10 + 1.6449 * \frac{17}{\sqrt{25} } ]

                                                  = [95.40 , 106.59]

Therefore, 90% confidence interval for the population mean test score is [95.40 , 106.59] .

7 0
3 years ago
What is 3,333,333 rounded tp
Luba_88 [7]
To the nearest tenth: 3,333,330

To the nearest hundred: 3,333,300

To the nearest thousand: 3,333,000

To the nearest ten thousand: 3,330,000

To the nearest hundred thousand: 3,300,000

To the nearest million: 3,000,000

Hope that helps :)
5 0
3 years ago
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