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jenyasd209 [6]
3 years ago
13

A right triangle is graphed on a coordinate plane. Find the length of the hypotenuse. Round your answer to the nearest tenth. ​

Mathematics
1 answer:
Hoochie [10]3 years ago
8 0

Answer:

7.6

Step-by-step explanation:

From the graph, we know the lengths of two legs.

  a = 3

  b = 7

Knowing this, we can use the Pythagorean Theorem to solve for c, the hypotenuse. (remember,  a^2 + b^2 = c^2)

c = √a2 + √b2  

= √(7)2 + √(3)2

= √49 + √9

= √58

= 7.6

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3 years ago
Secants L J and L M intersect and form an angle at point L. Solve for x.
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Answer:

x = 14  

Step-by-step explanation:

Assume your diagram is like the one below.

The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."

For your diagram, that means

\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}

Check:

\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}

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