X=20
Combine like terms and divide both sides by .24
Answer: 2 3/4
Step-by-step explanation: 1/4 + 3/4 is 1 whole plus 1/4+1/4 would equal the 1/2 you need.
So we are up to 3/4 already. 1 3/4 + 3/4 = 2 1/2
We need to add 2 more to get to 4 1/2
So the answer would be 2 3/4
2 3/4 + 1 3/4 = 4 1/2
Answer:
Mark talked on the phone for 120 minutes.
Step-by-step explanation:
18 - 12 = 6
6 ÷ .05 = <u>1</u><u>2</u><u>0</u>
Answer:
As 2021 and 1927 does not have any product of primes
HCF and LCM of 2020 and 1926 is shown below
Step-by-step explanation:
2020 = 2^2 × 5 × 101
1926 = 2 x 3^2 x 107
2 is the HCF
2 x 2 x 3 x 3 x 5 x 101 x 107 = 1945260
1945260 is the LCM
2022 and 1928 both have product of primes and their HCF and LCM is
1949208 is the LCF and 2 is the HCF
1949208 - 1945260 = 3948
3948/2 = 1974
2022-1928 = 94
2020 - 1926 = 94
1974/94 = 21
and brings us back to our year again.
Happy New Year to you.
We will investigate how to determine Hamilton paths and circuits
Hamilton path: A path that connect each vertex/point once without repetition of a point/vertex. However, the starting and ending point/vertex can be different.
Hamilton circuit: A path that connect each vertex/point once without repetition of a point/vertex. However, the starting and ending point/vertex must be the same!
As the starting point we can choose any of the points. We will choose point ( F ) and trace a path as follows:

The above path covers all the vertices/points with the starting and ending point/vertex to be ( F ). Such a path is called a Hamilton circuit per definition.
We will choose a different point now. Lets choose ( E ) as our starting point and trace the path as follows:

The above path covers all the vertices/points with the starting and ending point/vertex are different with be ( E ) and ( C ), respectively. Such a path is called a Hamilton path per definition.
One more thing to note is that all Hamilton circuits can be converted into a Hamilton path like follows:

The above path is a hamilton path that can be formed from the Hamilton circuit example.
But its not necessary for all Hamilton paths to form a Hamilton circuit! Unfortunately, this is not the case in the network given. Every point is in a closed loop i.e there is no loose end/vertex that is not connected by any other vertex.