Answer:
<h2>
<u>GIVEN</u><u> </u>- </h2>
- Water tank which is in a shape of right rectangular prism
Dimensions = 6 feet × 4 feet × 7 feet
<h3><u>TO</u><u> </u><u>FIND</u><u> </u><u>-</u><u> </u>
</h3>
<h2><u>SOLUTION</u>
- </h2>
<em><u>Using</u></em><em><u> </u></em><em><u>formula</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>surface</u></em><em><u> </u></em><em><u>area</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>right</u></em><em><u> </u></em><em><u>rectangular</u></em><em><u> </u></em><em><u>prism</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em>
Surface area =
L = length
w = width
h = height
( assumimg 6 feet = L , 4 feet = W , 7 feet = h)
Putting value of L, W and H in the equation. we get,
=2(4 × 6 + 7 × 6 + 7× 4)
= 2(24 + 42 + 28)
= 2( 94)
= 2 × 94
= 188
The object should be placed 20/cm from the lens so as to form its real image on the screen
<h3>Mirror equation</h3>
The mirror equation is given according to the expression below;
1/f = 1/u + 1/v
where
f is the focal length
u is the object distance
v is the image distance
Given the following parameters
f = 5cm
v = 20cm
Required
object distance u
Substitute
1/5 = 1/u +1/20
1/u = 1/5-1/20
1/u = 3/20
u = 20/3 cm
Hence the object should be placed 20/cm from the lens so as to form its real image on the screen
Learn more on mirror equation here; brainly.com/question/27924393
#SPJ1
Their frequency stays the same and their wavelength decreases
#1 √ 75
Answer : 5√3 or ≈ 8.66025
#2 √ 48
Answer : 4√3 or ≈ 6.9282
#3 √ 128
Answer : 8√2 or ≈ 11.31371
#4 √ 300
Answer : 10√3 or ≈ 17.32051
~~
#5 √⅔
Answer :
#6 √16/4
Answer : 2
#7 √ 6/8
Answer :
#8 √27/9
Answer : √ 2 or ≈ 1.73205
~~
I hope that helps you out!!
Any more questions, please feel free to ask me and I will gladly help you out!!
~Zoey