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3 years ago

15

The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).

1 answer:

valkas [14]3 years ago

4 0

Answer:

7, 12, 17...172 (34th term)

Step-by-step explanation:

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A number to the 9 power divided by the same number to the 6 power equals 27 what is the number

vfiekz [6]

Answer:

3

Step-by-step explanation:

n^9/ n^6 = 27

n^9 - 6 = 27

n^3 = 27

n = ∛27

n = 3

8 0

3 years ago

4+5(3-x)=4(8+2x)<br> send help please i’m taking a quiz and have NO clue

evablogger [386]

4+15-5x=32+8X
19-32=13X
-13=13X
X=-1

5 0

3 years ago

Read 2 more answers

Answer part B please

oksano4ka [1.4K]

1:5

Steps:
1. Add all the numbers
2. Take Derek’s number of votes and turn step 1’s answer and Derek’s number of votes into a ration:
3. You will now have 36:180
4. Simplify by a number they both share (36).
5. Your new simplified answer would be 1:5.

4 0

3 years ago

Read 2 more answers

The temperature readings from a thermocouple in a furnace fluctuate according to a cumulative distribution function,

Oliga [24]

Answer:

$P(x$

$P(x$

$P(x>808.40) = 0.58$

$P(x\le805.40\ or\ x\ge 808.40) = 0.85$

Step-by-step explanation:

Given:

$F(x) = \left\{\begin{array}{ll}{0} &; {x$

Solving (a): P(x < 810)

To solve this, we make use of:

$P(x$

Because

$800^\circ C \le 810 \le 820^\circ C$

So:

$F(x) = 0.05 * 810 -40$

$F(x) = 40.5 -40$

$F(x) = 0.5$

Hence:

$P(x$

Solving (b): P(x < 800)

To solve this, we make use of:

$P(x$

Because:

$x < 800^\circ C$

So:

$P(x$

Solving (c): P(x > 808.40)

Here, we make use of complement rule:

$P(x>808.40) = 1 - P(x \le 808.40)$

Where:

$P(x\le808.40) = 0.05x - 40$

$P(x\le808.40) = 0.05*808.40 - 40$

$P(x\le808.40) = 0.42$

So:

$P(x>808.40) = 1 - 0.42$

$P(x>808.40) = 0.58$

Solving (d) The probability that the temperature lies outside 805.60 and 808.40

First, we calculate the probability that it lies within.

This is represented as:

$P(805.40 < x < 808.40)$

This is calculated using:

$P(805.40 < x < 808.40) = F(808.40) - F(805.40)$

$P(805.40 < x < 808.40) = 0.05*808.40-40 - (0.05*805.40-40)$

$P(805.40 < x < 808.40) = 0.42 - (0.27)$

$P(805.40 < x < 808.40) = 0.42 - 0.27$

$P(805.40 < x < 808.40) = 0.15$

Using complement rule, the required probability is:

$P(x\le805.40\ or\ x\ge 808.40) = 1 - 0.15$

$P(x\le805.40\ or\ x\ge 808.40) = 0.85$

5 0

3 years ago

Can someone help me simplify these expressions

Gnesinka [82]

Answer:

$-6v^7$

$p^6$

Step-by-step explanation:

$-1v^3 \times -2v^2 \times -3v^2$

$-6v^{3+2+2}$

$-6v^7$

$1/2p^2 \times p^3 \times 2p$

$1/2p^2 \times 1p^3 \times 2p$

$1p^{2+3+1}$

$1p^6$

8 0

3 years ago