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3 years ago

Can someone plzz help me you got to zoom in !!!

Mathematics

2 answers:

Stella [2.4K]3 years ago

7 0

It’s a because that’s the as we’re

daser333 [38]3 years ago

3 0

1. 140 - The reason it would be one 40 is honestly a really simple explanation. Is the ratio of boys to girls in 7-2 and the amount of girls is 40. That means that per 1 number, is 20 people since 40 divided by 2 is 20. So if I do 2 x 7 that would be 140.

2. I didnt really understand this one sorryyy.

3. 1200 (same rule applies) - Since The ratio is 1:11 and the 1 represents 100 beans. If I doo 100 x 11 that would be 1100, then I would add the 1100 to the 100 (from the 1) and that would be 1200.

4. 6:7 - If I do 650 - 350 that would be 300. Which means the ratio would be 300:350. But once simplified the answer would be 6:7.

5. 1:2 - 720 - 240 is 480. Therefore the ratio would be 240:480. Once simplified, the ratio is 1:2.

Hope this helped. Good luck!!! xo

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In Leakwater township, there are two plumbers. On a particular day three Leakwater residents call village plumbers independently

Marianna [84]

Answer:

25% probability that all three residents will choose the same plumbe

Step-by-step explanation:

For each resident, there are only two possible outcomes. Either they choose the first plumbe, or they choose the second. The plumbers are chosen independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Each resident randomly chooses one of the two plumbers.

This means that $p = \frac{1}{2} = 0.5$

Three residents:

This means that $n = 3$

What is the probability that all three residents will choose the same plumb

This is P(X = 0)(all choose the second pumble) or P(X = 3)(all choose the first pumble). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.5)^{0}.(0.5)^{3} = 0.125$

$P(X = 3) = C_{3,3}.(0.5)^{3}.(0.5)^{0} = 0.125$

$p = P(X = 0) + P(X = 3) = 2*0.125 = 0.25$

25% probability that all three residents will choose the same plumbe

4 0

2 years ago

The product of 5 and y added to 3

olganol [36]

Subtract 5 and 3 then add 3 to the number you get? Idk I think thats what you do

8 0

3 years ago

Read 2 more answers

Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7

Zolol [24]

$f(x)=\begin{cases}1&\text{for }-7$

The Fourier series expansion of $f(x)$ is given by

$\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7$

where we have

$a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx$
$a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)$
$a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2$

The coefficients of the cosine series are

$a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx$
$a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)$
$a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}$
$a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}$

When $n$ is even, the numerator vanishes, so we consider odd $n$ , i.e. $n=2k-1$ for $k\in\mathbb N$ , leaving us with

$a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}$

Meanwhile, the coefficients of the sine series are given by

$b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx$
$b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)$
$b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}$
$b_n=\dfrac{7(-1)^{n+1}}{n\pi}$

So the Fourier series expansion for $f(x)$ is

$f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7$