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Zanzabum
3 years ago
12

Decimal expansion of -11/15

Mathematics
1 answer:
Alenkinab [10]3 years ago
3 0
Don’t listen to the links people -_- they mad annoying
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The m∠ACD = (4x + 4)° and m∠ABD = (6x - 14)°. Find m∠ACD.
densk [106]
The anwser is C because your suppose to line it up like this, 4x+4=6x-14, then you solve for x. Once you have x then you plug it in and solve. For your x you will get 9.
8 0
3 years ago
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What is the domain in interval notation?
Free_Kalibri [48]

Hello!


Interval notation is written using brackets or parentheses. Brackets mean that the value of the corresponding side is equal to the function. Parentheses are the opposite of brackets in this case, and it is not part of the equation.


I will post the graph of this equation below.


Therefore, the domain of this equation in interval notation is (-∞, 6/7).


Note that it is parentheses not brackets. The graph does not go past 6/7, and infinity is not a number, it is a concept.

3 0
4 years ago
An estimate for - ✓ 72 is<br> A.- 8.1<br> b. - 8.5<br> c. -9.1<br> d. -9.5
Agata [3.3K]
The answer is : b. -8.5
3 0
3 years ago
Emilia and Ferdinand took the same freshman chemistry course: Emilia in the fall, Ferdinand in the spring. Emilia made an 83 on
Wewaii [24]

Answer:

z = \frac{83-76}{8}=0.875

z = \frac{79-65}{12}=1.167

As we can see the z score for Ferdinad is higher than the z score for Emilia so on this case we can conclude that Ferdinand was better compared with his group of reference.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Emilia case

Let X the random variable that represent the scores of a test, and we know that

Where \mu=76 and \sigma=8

The z score formula is given by:

z=\frac{x-\mu}{\sigma}

Since Emilia made 83 points we can find the z score like this:

z = \frac{83-76}{8}=0.875

Ferdinand case

Let X the random variable that represent the scores of a test, and we know that

Where \mu=65 and \sigma=12

The z score formula is given by:

z=\frac{x-\mu}{\sigma}

Since Ferdinand made 79 points we can find the z score like this:

z = \frac{79-65}{12}=1.167

As we can see the z score for Ferdinad is higher than the z score for Emilia so on this case we can conclude that Ferdinand was better compared with his group of reference.

5 0
3 years ago
100 PTS! HELP QUICK!!
Nina [5.8K]

Answer:

thanx bro.............. .. ...

7 0
3 years ago
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