All there is, is a picture. Is there a question?
d = distance between the two cities
v₁ = average speed while going from chicago to kansas city = 440 knots
t₁ = time taken to travel distance going from chicago to kansas city
time taken to travel distance going from chicago to kansas city is given as
t₁ = d/v₁
t₁ = d/440 eq-1
v₂ = average speed while going from kansas city to chicago = 110 knots
t₂ = time taken to travel distance going from kansas city to chicago
time taken to travel distance going from kansas city to chicago is given as
t₂ = d/v₂
t₂ = d/110 eq-2
Given that :
t₂ = t₁ + 3
using eq-1 and eq-2
(d/110) = (d/440) + 3
d = 440
Answer:
X from 0 to 21
Y from 0 to 7
Z from 0 to 3
Step-by-step explanation:
Since we are being asked by the integration limits in first octant (positive x, positive y and positive z) we need to know where does the plane intersect this axes. For this we have:
for x=0 and y=0
7z=21
z=3
for x=0 and z=0
3y=21
y=7
for z=0 and y=0
x=21
This means that the integration limits are:
X from 0 to 21
Y from 0 to 7
Z from 0 to 3
Negative slope and shifted 5 down on the y axis with a root at x=-5
