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Kipish [7]
3 years ago
9

Baby Kristen wants to arrange 7 blocks in a row. How many different arrangements can the baby make?

Mathematics
1 answer:
Mrrafil [7]3 years ago
8 0

Answer:

7! = 7x6x5x4x3x2x1 =5040

there are 5040 arrangements.

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April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3
vlada-n [284]

Answer:

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = 5\frac{1}{4}\ hrs

5\frac{1}{4}\ hrs can be Rewritten as \frac{21}{4}\ hrs

Number of Hours Carl worked on Math project = \frac{21}{4}\ hrs

Number of Hours Sonia worked on Math project = 6\frac{1}{2}\ hrs

6\frac{1}{2}\ hrs can be rewritten as \frac{13}{2}\ hrs

Number of Hours Sonia worked on Math project = \frac{13}{2}\ hrs

Number of Hours Tony worked on Math project = 5\frac{2}{3}\ hrs

5\frac{2}{3}\ hrs can be rewritten as \frac{17}{3}\ hrs.

Number of Hours Tony worked on Math project = \frac{17}{3}\ hrs.

Now Given:

April worked 1\frac{1}{2} times as long on her math project as did Carl.

1\frac{1}{2}  can be Rewritten as \frac{3}{2}

Number of Hours April worked on math project = \frac{3}{2} \times Number of Hours Carl worked on Math project

Number of Hours April worked on math project = \frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs

Also Given:

Debbie worked 1\frac{1}{4} times as long as Sonia.

1\frac{1}{4}  can be Rewritten as \frac{5}{4}.

Number of Hours Debbie worked on math project = \frac{5}{4} \times Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = \frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs

Also Given:

Richard worked 1\frac{3}{8} times as long as tony.

1\frac{3}{8} can be Rewritten as \frac{11}{8}

Number of Hours Richard worked on math project = \frac{11}{8} \times Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = \frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs

Hence We will match each student with number of hours she worked.

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

5 0
3 years ago
Read 2 more answers
A restaurant chef bought potatoes at four different stores. The table shows the amount of the potatoes she bought at each store
hichkok12 [17]

Answer:

The way to answer this question is to find out the price per pound potato by dividing the amount the restaurant chief paid by the number of pounds bought.

Your question lacks details on the pounds bought in the other stores so I will assume these figures and you can use it as a reference.

Restaurant B - 2 pounds

Restaurant C - 12 pounds

Restaurant D - 5 pounds

Price per pound

Restaurant A = 6.60/8

= $0.83

Restaurant B = 3.50/2

= $1.75

Restaurant C = 9.75/12

= $0.82

Restaurant D = 4.80/8

= $0.96

<u><em>Restaurant C </em></u><em>has the lowest price per pound for potatoes. </em>

3 0
3 years ago
Write a recursive rule for the sequence.
Vadim26 [7]

Answer:

f(n)=f(n-1)+f(n-2)

f(1)=1x

f(2)=1x

Step-by-step explanation:

This is the fibonacci sequence with each term times x.

Notice, you are adding the previous two terms to get the third term per consecutive triples of the sequence.

That is:

1x+1x=2x

1x+2x=3x

2x+3x=5x

3x+5x=8x

So since we need the two terms before the third per each consecutive triple in the sequence, our recursive definition must include two terms of the sequence. People normally go with the first two.

f(1)=1x since first term of f is 1x

f(2)=1x since second term of f is 1x

Yes, I'm naming the sequence f.

So I said a third term in a consecutive triple of the sequence is equal to the sum of it's two prior terms. Example, f(3)=f(2)+f(1) and f(4)=f(3)+f(2) and so on...

Note, the term before the nth term is the (n-1)th term and the term before the (n-1)th term is the (n-2)th term. Just like before the 15th term you have the (15-1)th term and before that one you have the (15-2)th term. That example simplified means before the 15th term you have the 14th and then the 13th.

So in general f(n)=f(n-1)+f(n-2).

So the full recursive definition is:

f(n)=f(n-1)+f(n-2)

f(1)=1x

f(2)=1x

8 0
3 years ago
A machine packs 2/5 of a box every 1/2 minute. What is the number of boxes per minute packed? Why?
Alla [95]
If it is packed 2/5 in 1/2 minutes

1 minute =2/5*2=4/5 or 0.8 boxes/min
4 0
3 years ago
Look at the two-dimensional net shown. A rectangular pyramid. The rectangular base has a length of 10 meters and height of 3 met
valentina_108 [34]

Answer: Here.

The Solid formed by the net will be a rectangular pyramid.

There are TWO sets of opposite congruent triangular faces.

The base has an area of 30m2

Step-by-step explanation: Don't listen to the B and C dude.

3 0
3 years ago
Read 2 more answers
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