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3 years ago

Baby Kristen wants to arrange 7 blocks in a row. How many different arrangements can the baby make?

Mathematics

1 answer:

Mrrafil [7]3 years ago

8 0

Answer:

7! = 7x6x5x4x3x2x1 =5040

there are 5040 arrangements.

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Which shape has two sets of parallel sides only?

soldier1979 [14.2K]

Answer:

all of the above to be honest

because they all have 2 pairs of parallel sides

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3 years ago

I’ve been stuck can someone help

never [62]

Answer:

(a). $A_{x}$ = $\left[\begin{array}{cc}12&-4\\66&6\end{array}\right]$

Step-by-step explanation:

$\left \{ {{5x-4y=12} \atop {3x+6y=66}} \right.$

A = $\left[\begin{array}{cc}5&-4\\3&6\end{array}\right]$

$A_{x}$ = $\left[\begin{array}{cc}12&-4\\66&6\end{array}\right]$

$A_{y}$ = $\left[\begin{array}{cc}5&12\\3&66\end{array}\right]$

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3 years ago

Between which two consecutive integers does the square root of 115 lie

Harrizon [31]

It lies between 10 and 11<span />

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3 years ago

Read 2 more answers

100 feet of yarn to make a bracelet.same amount of yarn to make each bracelet.. expression that will find amount of yarn

castortr0y [4]

Let x be the number of bracelets you can make
Amount of yarn needed = 100x

8 0

4 years ago

Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{12},0)(± 12 ,0)left parenthesis, plus min

lora16 [44]

Answer:

$\mathbf{\dfrac{x^2}{49^2} +\dfrac{y^2}{37^2} =1}$

Step-by-step explanation:

Given that :

the foci of the ellipse is (±√12,0) and C0-vertices are (0,±√37)

The foci are (-C,0) and (C ,0)

the focus has x-coordinates so the focus is lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so C0-vertices are (0,±√37)

The given focus C = ae = √12

Given co-vertices ( minor axis) (0,±b) = (0,±√37)

b= √37

We can therefore express the relation between the focus and semi major axes and semi minor axes as:

$\mathbf{c^2 = a^2 - b^2 } \\ \\ \mathbf{a^2 = c^2 + b^2 } \\ \\ \mathbf{c^2 = ( \sqrt12)^2 - (\sqrt 37)^2 } \\ \\ \mathbf{c^2 = 49 } \\ \\ \mathbf{c = \sqrt{49 }}$

The equation of ellipse formula is:

$\dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1$

and we know that $\mathbf{a=\sqrt{49} \ \ and \ \ b=\sqrt{37}}$

Thus ; the equation of the ellipse at the origin is

$\mathbf{\dfrac{x^2}{49^2} +\dfrac{y^2}{37^2} =1}$

3 0

4 years ago