Suppose y varies jointly as x and z. If y=15 when x=1/2 and z=6, what is the constant of variation?
2 answers:
Answer:
k = 5
Step-by-step explanation:
Given y varies jointly as x and z then the equation relating them is
y = kxz ← k is the constant of variation
To find k use the condition y = 15 when x =
and z = 6 , then
15 = k ×
× 6 = 3k ( divide both sides by 3 )
5 = k
Answer:
y= 15
Step-by-step explanation:
Y= Kxz
y=6 x=1/2 z=6
15= K (1/2) (6)
15= K (3)
K= 5
SO
y= (5) (1/2) (6)
Y= 15
You might be interested in
Answer:
2 points
Step-by-step explanation:
10-14=-4
-4+6=2 or
10+6=16
16-14=2
2
it like trying to imagine re-folding back a cardboard box
The answer is 0.8! Hope this helped
Answer:
y=2x+17
Step-by-step explanation:
y-y1=m(x-x1)
y-1=2(x-(-8))
y-1=2(x+8)
y=2x+16+1
y=2x+17
9:12, 18:24,6:8
3*3=9 and 4*3=12
3*6=18 and 4*6=24
3*2=6 and 4*2=8