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hammer [34]
2 years ago
7

Suppose y varies jointly as x and z. If y=15 when x=1/2 and z=6, what is the constant of variation?

Mathematics
2 answers:
Elden [556K]2 years ago
8 0

Answer:

k = 5

Step-by-step explanation:

Given y varies jointly as x and z then the equation relating them is

y = kxz ← k is the constant of variation

To find k use the condition y = 15 when x = \frac{1}{2} and z = 6 , then

15 = k × \frac{1}{2} × 6 = 3k ( divide both sides by 3 )

5 = k

Mashcka [7]2 years ago
4 0

Answer:

y= 15

Step-by-step explanation:

Y= Kxz

y=6  x=1/2   z=6

15= K (1/2) (6)

15= K (3)

K= 5

SO

y= (5) (1/2) (6)

Y= 15

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3 0
2 years ago
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Of the basketball players on the team, exactly 75% of the players have heights above 180

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