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2 years ago

Suppose y varies jointly as x and z. If y=15 when x=1/2 and z=6, what is the constant of variation?

Mathematics

2 answers:

Elden [556K]2 years ago

8 0

Answer:

k = 5

Step-by-step explanation:

Given y varies jointly as x and z then the equation relating them is

y = kxz ← k is the constant of variation

To find k use the condition y = 15 when x = $\frac{1}{2}$ and z = 6 , then

15 = k × $\frac{1}{2}$ × 6 = 3k ( divide both sides by 3 )

5 = k

Mashcka [7]2 years ago

4 0

Answer:

y= 15

Step-by-step explanation:

Y= Kxz

y=6 x=1/2 z=6

15= K (1/2) (6)

15= K (3)

K= 5

y= (5) (1/2) (6)

Y= 15

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We have that

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therefore

case a)
$\frac{(x+4)}{3} * \frac{x}{6}$
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case b)
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case c)
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case e)
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Hence

the answer is

$\frac{(x+4)}{3} * \frac{x}{6}$

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<h3>What are proportional relationships?</h3>

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brainly.com/question/2143065

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