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hammer [34]
3 years ago
7

Suppose y varies jointly as x and z. If y=15 when x=1/2 and z=6, what is the constant of variation?

Mathematics
2 answers:
Elden [556K]3 years ago
8 0

Answer:

k = 5

Step-by-step explanation:

Given y varies jointly as x and z then the equation relating them is

y = kxz ← k is the constant of variation

To find k use the condition y = 15 when x = \frac{1}{2} and z = 6 , then

15 = k × \frac{1}{2} × 6 = 3k ( divide both sides by 3 )

5 = k

Mashcka [7]3 years ago
4 0

Answer:

y= 15

Step-by-step explanation:

Y= Kxz

y=6  x=1/2   z=6

15= K (1/2) (6)

15= K (3)

K= 5

SO

y= (5) (1/2) (6)

Y= 15

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The price of a car increased by 7% which expression can be used to calculate the new price of the car
julsineya [31]

Answer: P * ( 1 + 7%)

Step-by-step explanation:

You included no options but the expression should go something like this:

Pn = P * ( 1 + 7%)

Where Pn is the new price

P is the current price

<em>The above formula will show the new price given the current price. </em>

6 0
3 years ago
The distance between the points (-2, -4) and (3,8) is?
forsale [732]

Answer:

(5,4)

Step-by-step explanation:

6 0
3 years ago
Please help
OlgaM077 [116]
First, we're going to see the candies per minute that machine C packs.
150 / 2 = 75

Now that we know that machine C packs 75 candies per minute, we're going to multiply the candies machine C makes by 11 minutes.
75 x 11 = 825

We're now gonna do the same with machine D.
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Then we're going to find the difference between machine C and machine D, we do this because the question basically asks how much more candies can machine D pack than machine C.
1430 - 825 = 605 candies.

This is how we find our final answer.

Our answer would be D) 605.

Hope this helps!~
4 0
3 years ago
Find -1/5 + (-3/5) in simplest form​
guapka [62]

Answer:  -0.8 or -4/5

Step-by-step explanation:

1/5 + 3/5 = 4/5 and u put the negatives so its -4/5. HOPE THIS HELPS :3 !!!!

6 0
4 years ago
Select all of the following true statements if R = real numbers, I = integers, and W = {0, 1, 2, ...}.
Vinvika [58]

Answer and Step-by-step explanation:

We will begin to solve this problem by defining first what the sets' elements really are.

R consists of real numbers. This means that this set contains all the numbers, rational or not.

Z is composed of whole numbers. Integers include all negative and positive numbers as well as zero (it's basically a set of whole numbers and their negated values).

W, on the other hand, has 0,1,2, and its elements are onward. Those numbers are referred to as whole numbers.

W ⊂ Z is TRUE. Z contains all the numbers as stated earlier, and W is a subset of it.

R ⊂ W is FALSE. Not all numbers are complete numbers. Complete numbers must be rational and represented fractionless. These requirements are not met by those real numbers.

0 ∈ Z is TRUE.  Zero is just an integer so it is a component of Z.

∅ ⊂ R is TRUE. A set i.e null be R subset, and each and every set is a general set. Moreover, there were not single elements in a null set, so it spontaneous became a non empty set subset through description as there is no element of R.

{0,1,2,...} ⊆ W is TRUE. The set on the left is precisely what is specified in the statement for problem for W. (The bar below the subset symbol simply implies that the subset is not rigid, because the set on the left may be equal to the set on the right. Without it, the argument would be incorrect, because a strict subset needs that the two sets not be identical).

-2 ∈ W is FALSE. W's only made up of whole numbers and not their negated equivalents.

4 0
4 years ago
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