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hammer [34]
2 years ago
7

Suppose y varies jointly as x and z. If y=15 when x=1/2 and z=6, what is the constant of variation?

Mathematics
2 answers:
Elden [556K]2 years ago
8 0

Answer:

k = 5

Step-by-step explanation:

Given y varies jointly as x and z then the equation relating them is

y = kxz ← k is the constant of variation

To find k use the condition y = 15 when x = \frac{1}{2} and z = 6 , then

15 = k × \frac{1}{2} × 6 = 3k ( divide both sides by 3 )

5 = k

Mashcka [7]2 years ago
4 0

Answer:

y= 15

Step-by-step explanation:

Y= Kxz

y=6  x=1/2   z=6

15= K (1/2) (6)

15= K (3)

K= 5

SO

y= (5) (1/2) (6)

Y= 15

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Three of the four towns are on the vertices of the triangle ΔCBD, through

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<h3>Response:</h3>
  • The bearing of D from B is approximately <u>209.05°</u>

<h3>Method by which the bearing is found;</h3>

From the given information, we have;

AC = AB = 25 km

∠BAC = 90° (definition of angle between north and east)

ΔABC = An isosceles right triangle (definition)

∠ACD = ∠ABC = 45° (base angles of an isosceles right triangle)

tan(\angle ABD) = \dfrac{45}{25}

  • \angle ABD = arctan \left(\dfrac{45}{25} \right)  \approx 60.945^{\circ}

The bearing of <em>D</em> from <em>B</em> is the angle measured from the north of <em>B</em> to the

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<em />

Therefore;

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3 years ago
Can you simplify 3(x+2) = 3x+6 in distributive property
Vanyuwa [196]

Hello XD

3(x+2) = 3x+6

Distributive property

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Subtract 6 from both sides

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