Answer:
If (K + 1)^2 = 2n + (n^2)/2, then the answer is Yes, else No.
Step-by-step explanation:
Sum of first K + 1 odd numbers (S): 1 + 3 + 5 + ... + (2K - 3) + (2K - 1) + (2K + 1).
(1 + 3 + 5 + ... + (2K - 3) + (2K - 1) + (2K + 1)) + ((2K + 1) + (2K - 1) + (2K - 3) + ... + 5 + 3 + 1 ) = (2K + 2) + (2K + 2) + (2K + 2) + ... + (2K + 2) + (2K + 2) + (2K + 2) (repeat K + 1 times) = (2K + 2)(K + 1) = 2S
2S = (2K + 2)(K + 1)
S = (2K + 2)(K + 1)/2
S = (2K^2 + 4K + 2)/2
S = K^2 + 2K + 1
S = (K + 1)^2
(4n + n^2)/2 = 2n + (n^2)/2
I don’t know the answer but I just want to say comedown you can do this
Answer is Median Option(C.) since it divides RS into two equal halves i.e.RQ=QS=7
Hope this helps....
Answer:
1. The preimage and image are congruent
2. Any line segment connecting the corresponding points between the preimage and image is bisected by the line of reflection
3. Corresponding angles on the preimage and image are congruent
4. Corresponding points of the preimage and image are equidistant from the line of reflection.
making x the subject
substitute into second equation
by solving, y=5
substitute into first equation
by solving, x=-3
Therefore the ordered pair is (-3,5)
