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2 years ago

7

A jewelry store buys a gold watch sell.

1 answer:

Reika [66]2 years ago

3 0

Answer:

-2565

Step-by-step explanation:

because all you have to do is subtract the percentage and the actual price of the jewelry so yeah he's paid that much money so yeah

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1. Which of these fractions has the greatest value?" Mark only one oval. 7/12 5/6 2/3

ddd [48]

Answer:

5/6

Step-by-step explanation:

6 0

2 years ago

Evaluate the line integral, where c is the given curve. c y3 ds,

postnew [5]

Parameterizing $\mathcal C$ by

$\mathbf r(t)=(t^3,t)$

with $0\le t\le2$ , we have

$\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt=\sqrt{(3t^2)^2+1^2}\,\mathrm dt=\sqrt{9t^4+1}\,\mathrm dt$

So

$\displaystyle\int_{\mathcal C}y^3\,\mathrm ds=\int_{t=0}^{t=2}t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_0^236t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_{u=1}^{u=145}\sqrt u\,\mathrm du$
$=\dfrac{145^{3/2}-1}{54}$

5 0

3 years ago

Y=-x^2<br> y=-7x^2<br> y=2/3x^2

valentinak56 [21]

Y = -x²
y = -7x²
<u>y = 2/3x²</u>
<u>3y</u> = <u>-7 1/3x²
</u> 3 3
y = -2 4/9x

7 0

3 years ago

The circumference of the bike tire above is 83.524 inches. What is the radius of the bike tire?

dezoksy [38]

Divide 83.524 by pi then take half of that answer .
the answer should be 13.29 or 13.3

3 0

3 years ago

Giá trị x thoả mãn x(x − 3) + x − 3 =0 là

svet-max [94.6K]

Here we will use the trial and error method.

We will try putting different values of x.

<h3 /><h3>1st of all</h3><h3>x=1</h3>

$\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}$

<h2>Now,</h2><h3>x=2</h3>

$\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}$

<h2>Again,</h2><h3>x=3</h3>

$\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}$

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>

5 0

3 years ago