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Amanda [17]
3 years ago
9

Thank you to anyone that helps

Mathematics
2 answers:
Margarita [4]3 years ago
7 0

Answer:

10

Step-by-step explanation:

1 Subtract 150150 from both sides.

10x=200+5x-150

10x=200+5x−150

2 Simplify  200+5x-150200+5x−150  to  5x+505x+50.

10x=5x+50

10x=5x+50

3 Subtract 5x5x from both sides.

10x-5x=50

10x−5x=50

4 Simplify  10x-5x10x−5x  to  5x5x.

5x=50

5x=50

5 Divide both sides by 55.

x=\frac{50}{5}

x=

5

50

​

6 Simplify  \frac{50}{5}

5

50

​

  to  1010.

x=10

x=10

Done

IceJOKER [234]3 years ago
4 0
I agree with the other person I think that that is the right Answer
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Step-by-step explanation: with what?

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An adjustable ladder on the back of the firetruck is needed for firefighters to climb to very high buildings. The maximum angle
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Jameson pays $39.90 for 3.8 pounds of almonds. What is the price per pound of almonds?
IgorLugansk [536]

Step-by-step explanation: The price of3.8 pounds of almonds=$39.90 thus we can write Hence the price of almonds is $10.50 per pounds.

AWNSERS:$10.50

3 0
3 years ago
Read 2 more answers
Given: KLMN is a trapezoid m∠K = 90°, m∠N = 45° LK = LM = 10 Find: KN, Area of KLMN
Ilya [14]
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
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5 0
3 years ago
A researcher wants to estimate the percentage of all adults that have used the Internet to seek pre-purchase information in the
Lubov Fominskaja [6]

Answer:

The required sample size for the new study is 801.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

25% of all adults had used the Internet for such a purpose

This means that \pi = 0.25

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

What is the required sample size for the new study?

This is n for which M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.25*0.75)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.25*0.75}

\sqrt{n} = \frac{1.96\sqrt{0.25*0.75}}{0.03}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.25*0.75}}{0.03})^2

n = 800.3

Rounding up:

The required sample size for the new study is 801.

4 0
3 years ago
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