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Vsevolod [243]
3 years ago
12

Ms. Parker determined that the mean test score in her first-period class

Mathematics
1 answer:
cluponka [151]3 years ago
6 0

Answer:

B. Period 1 had scores that were less spread out around the mean than

Period 2

Step-by-step explanation:

Because the standard deviation of Period 2's scores is greater than that of Period 1's, the test scores for Period 2 are going to be more spread out than Period 1's test scores. B is the most logical choice in this case.

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Can someone please answer this?
galina1969 [7]
Since we know the side length of the square (6), we can calculate its diagonal using pythagoras.

diag d = √(6²+6²) = 6√2 in

The diagonal is also the diameter of the circle! So the radius of the circle is half of that:

radius r = d/2 = 3√2 in

The area of the circle is πr² = π(3√2)² = 18π in²
5 0
3 years ago
Ibuki factored 12x^7as (4x^3)(3x^4)
Marina86 [1]

Answer:

Both are correct.

Step-by-step explanation:

The key understanding here is that you can factor a monomial in many different ways!

To check if any of the factorizations is correct, we can multiply the factors and see if their product is really 12x^712x

7

12, x, start superscript, 7, end superscript.

Hint #22 / 4

\begin{aligned} (\blueD{4}\maroonD{x^3})(\blueD{3}\maroonD{x^4})&=(\blueD{4})(\blueD{3})(\maroonD{x^3})(\maroonD{x^4}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}

(4x

3

)(3x

4

)

​

 

=(4)(3)(x

3

)(x

4

)

=12x

7

​

So Ibuki is correct!

Hint #33 / 4

\begin{aligned} (\blueD{2}\maroonD{x^6})(\blueD{6}\maroonD{x})&=(\blueD{2})(\blueD{6})(\maroonD{x^6})(\maroonD{x}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}

(2x

6

)(6x)

​

 

=(2)(6)(x

6

)(x)

=12x

7

​

So Melodie is also correct!

Both Ibuki and Melodie are correct.

8 0
3 years ago
Y = 0.95X 7.95<br> Write and solve a linear equation to find how many songs he downloaded
Dmitry [639]
0.95 x 7.95 = 7.5525
5 0
3 years ago
Given the functions f(x) = x2 + 6x − 1, g(x) = –x2 + 2, and h(x) = 2x2 − 4x + 3, rank them from least to greatest based on their
kotegsom [21]
 You can find an axis of symmmetry of quadratic function by using this formula:

x=-\dfrac{b}{2a} \\ \\ \hbox{Where function is} \ \ f(x)=ax^2+bx+c \ \ \hbox{assuming} \ \ a\neq 0

An axis of f(x):

x=-\dfrac{6}{2 \cdot 1}=-\dfrac{6}{2}=-3

Of g(x):

x=-\dfrac{0}{2 \cdot (-1)}=\dfrac{0}{2}=0

Of h(x):

x=-\dfrac{-4}{2 \cdot 2}=\dfrac{4}{4}=1

At least to greatest you've got  -3, 0,  1   so f(x),  g(x),  h(x). Answer a
6 0
3 years ago
How do you solve this? 4x(a-4)
masya89 [10]

Answer:

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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