if it has a diameter of 8, that means its radius is half that, or 4.
![\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=4\\ h=5 \end{cases}\implies V=\cfrac{\pi (4)^2(5)}{3}\implies V=\cfrac{80\pi }{3} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{using~\pi =3.14}{V= 83.7\overline{3}}~\hfill](https://tex.z-dn.net/?f=%20%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%0AV%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D~~%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Ar%3D4%5C%5C%0Ah%3D5%0A%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20%284%29%5E2%285%29%7D%7B3%7D%5Cimplies%20V%3D%5Ccfrac%7B80%5Cpi%20%7D%7B3%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A~%5Chfill%20%5Cstackrel%7Busing~%5Cpi%20%3D3.14%7D%7BV%3D%2083.7%5Coverline%7B3%7D%7D~%5Chfill%20)
Answer:
B = (5,4), C = (-5, -4), D = (5, -4), A = (-5, 4)
Step-by-step explanation:
look at x axis first (horizontal), then y axis (vertical)
Put them into y=mx+b
y=1/3x -1
y=2/3x-4
Graph them. Where they touch is your answer. No touch? No solution. Same line? Infinite solutions.
Second set: Same thing.
Solution to first set is (9,2)
Answer:
A. <em>A </em>and <em>F</em>.
Step-by-step explanation:
By observing the number line given, you can assume that in between -4 and -6 would be the number -5, replaced by the variable <em>A</em>, and the same thing with 4 and 6, where 5 is replaced by <em>F</em>.
Answer:
Correct answer: Hmax = 22.11 m
Step-by-step explanation:
The subject of this problem is a vertical shot upwards, to which the following formula applies:
V₀² - V² = 2 · g · H where is:
V₀ - initial velocity
V - final velocity
g = 10 m/s²
H - final height
Given:
V₀ = 69 ft/s = 21.03 m/s
V = 0 m/s
Hmax = ?
V₀² = 2 · g · Hmax ⇒ Hmax = V₀² / 2 · g
Hmax = 21.03² / 2 · 10 = 442.26 / 20 = 22.11 m
Hmax = 22.11 m
God is with you!!!
