Ms. Parker determined that the mean test score in her first-period class
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The outlier of a dataset is a data element that is relatively far from the remaining data elements
- <em>99 is an outlier of pet group</em>
- <em>See attachment for the parallel box plots</em>
<u>(a) Prove that 99 is an outlier for Pet</u>
We have:
<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>
The quartiles positions are:
So, we have:
From the pet group:
The data elements at the 4th and 12th positions are 68 and 79
So, we have:
The lower and upper limits of the outlier are:
So, we have:
This means that data below 51.5 or above 95.5 are outliers.
<em>Hence, 99 is an outlier because 99 is greater than 95.5</em>
<u>(b) The parallel box plot</u>
The three groups are:
<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>
<em>Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82 </em>
<em>Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99</em>
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See attachment for the parallel box plots
Read more about box plots and outliers at:
Answer:
Total paper required = 165 cm²
Step-by-step explanation:
Paper required to cover the entire block = (Surface area of the prism at the base - area of the top of the prism) + Lateral surface area of the pyramid
Surface area of the rectangular prism = 2(lb + bh + hl)
(here l, b, h are the length, width and height respectively)
= 2(5×5 + 5×4 + 4×5)
= 2(25 + 20 + 20)
= 2×65
= 130 cm²
Area of the top of the prism = (side)²
= 5²
= 25 cm²
Lateral area of the square pyramid = 4 × Area of one lateral side
= 4 ×
= 4 ×
= 60 cm²
Total paper required = (130 - 25) + 60
= 105 + 60
= 165 cm²