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3 years ago

Ms. Parker determined that the mean test score in her first-period class

Mathematics

1 answer:

cluponka [151]3 years ago

6 0

Answer:

B. Period 1 had scores that were less spread out around the mean than

Period 2

Step-by-step explanation:

Because the standard deviation of Period 2's scores is greater than that of Period 1's, the test scores for Period 2 are going to be more spread out than Period 1's test scores. B is the most logical choice in this case.

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Help pls!!!!!!!!!!!!!!!!!!

Sidana [21]

Answer:

I can't see the file

Step-by-step explanation:

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2 years ago

bacteria in a culture increased Exponentially. If the the number of bacteria doubles in 3 hours in how many hours will the numbe

Elis [28]

6 hours because
double- 3 hours
triple- 6 hours

7 0

3 years ago

Help me please, need this done now.

Nikolay [14]

simplifying $\frac{\sqrt{4}}{\sqrt[3]{4}}$ we get $4^{\frac{1}{6}}$

Option B is correct.

Step-by-step explanation:

We need to simplify: $\frac{\sqrt{4}}{\sqrt[3]{4}}$

Solving:

$\frac{\sqrt{4}}{\sqrt[3]{4}}$

We know that √ = 1/2 and ∛=1/3

$\frac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}$

Applying exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$=4^{\frac{1}{2}-\frac{1}{3}}\\=4^{\frac{3-2}{6}}\\=4^{\frac{1}{6}}$

So, simplifying $\frac{\sqrt{4}}{\sqrt[3]{4}}$ we get $4^{\frac{1}{6}}$

Option B is correct.

Keywords: Solving Exponents

Learn more about Solving Exponents at:

#learnwithBrainly

6 0

3 years ago

Solve the absolute value equation 4 − |x| = 1. 20 Points

pav-90 [236]

Answer:

Your answer should be A x=+- 3

Step-by-step explanation:

7 0

3 years ago

Find the distance, to the nearest tenth, from T(4-2) to U(-2,3)

kiruha [24]

Distance = SQRT(x^2+y^2)
x = 4 - (-2) = 6
y = 3 - 2 = 1

distance = SQRT(6^2 + 1^2) = SQRT(36+1) = SQRT(37) = 6.1

4 0

3 years ago