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drek231 [11]
3 years ago
14

X^2 + 1/2x + _ =2 + _

Mathematics
2 answers:
Irina18 [472]3 years ago
8 0

Answer:

  • 0.5x  x (2x+1)

Step-by-step explanation:

maw [93]3 years ago
3 0
The blanks should be 0
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Suppose that, for every lot of 100 computer chips a company produces, an average of 1.4 are defective. Another company buys many
Vesna [10]

Answer:

P(X\leq 3)= P(X=0) +P(X=1)+P(X=2) +P(X=3)

And we can find the individual probabilities like this:

P(X=0) =1.4^0 \frac{e^{-1.4}}{0!}= 0.2466

P(X=1) =1.4^1 \frac{e^{-1.4}}{1!}= 0.3452

P(X=2) =1.4^2 \frac{e^{-1.4}}{2!}= 0.2417

P(X=3) =1.4^3 \frac{e^{-1.4}}{3!}= 0.1128

And replacing we got:

P(X\leq 3)= P(X=0) +P(X=1)+P(X=2) +P(X=3)=0.2466+ 0.3452+0.2417+0.1128=0.9463

Step-by-step explanation:

Definitions and concepts

The Poisson process is useful when we want to analyze the probability of ocurrence of an event in a time specified. The probability distribution for a random variable X following the Poisson distribution is given by:

P(X=x) =\lambda^x \frac{e^{-\lambda}}{x!}

And the parameter \lambda=1.4 represent the average ocurrence rate per unit of time.

Solution to the problem

For this case the batch would be rejected if we found more than 3 defects, so then the probability of accept the batch would be given by:

P(X\leq 3)= P(X=0) +P(X=1)+P(X=2) +P(X=3)

And we can find the individual probabilities like this:

P(X=0) =1.4^0 \frac{e^{-1.4}}{0!}= 0.2466

P(X=1) =1.4^1 \frac{e^{-1.4}}{1!}= 0.3452

P(X=2) =1.4^2 \frac{e^{-1.4}}{2!}= 0.2417

P(X=3) =1.4^3 \frac{e^{-1.4}}{3!}= 0.1128

And replacing we got:

P(X\leq 3)= P(X=0) +P(X=1)+P(X=2) +P(X=3)=0.2466+ 0.3452+0.2417+0.1128=0.9463

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yKpoI14uk [10]

Answer: 66

Step-by-step explanation:

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Please help me with this
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Answer:

484*pi cm^2

Step-by-step explanation:

becasue 4 times 121 is 484, 121 because 11^2 is 121

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