Answer:
![\sqrt[6]{432}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B432%7D)
Step-by-step explanation:
![\sqrt[3]{4}\cdot\sqrt{3}=4^{\frac{1}{3}}\cdot3^\frac{1}{2}=(2^2)^\frac{1}{3}\cdot3^\frac{1}{2}=(2^\frac{4}{3})^\frac{1}{2}\cdot3^\frac{1}{2}=(2^\frac{4}{3}\cdot3)^\frac{1}{2}=(2^4\cdot27)^\frac{1}{6}=432^\frac{1}{6}=\sqrt[6]{432}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4%7D%5Ccdot%5Csqrt%7B3%7D%3D4%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5Ccdot3%5E%5Cfrac%7B1%7D%7B2%7D%3D%282%5E2%29%5E%5Cfrac%7B1%7D%7B3%7D%5Ccdot3%5E%5Cfrac%7B1%7D%7B2%7D%3D%282%5E%5Cfrac%7B4%7D%7B3%7D%29%5E%5Cfrac%7B1%7D%7B2%7D%5Ccdot3%5E%5Cfrac%7B1%7D%7B2%7D%3D%282%5E%5Cfrac%7B4%7D%7B3%7D%5Ccdot3%29%5E%5Cfrac%7B1%7D%7B2%7D%3D%282%5E4%5Ccdot27%29%5E%5Cfrac%7B1%7D%7B6%7D%3D432%5E%5Cfrac%7B1%7D%7B6%7D%3D%5Csqrt%5B6%5D%7B432%7D)
Answer:
everything is correct
Step-by-step explanation:
you did a good job
Given :-
- The general term of a sequence is given by aₙ=43-3(n-1) .
To Find :-
- The first four terms of the sequence.
Solution :-
The given expression is 
→ aₙ=43-3(n-1)
where n > 0
<u>Finding</u><u> the</u><u> </u><u>first </u><u>term </u><u>:</u>
Substituting n = 1 , we have ,
→ T1 = 43 - 3(1-1)
→ T1 = 43 - 3*0
→ T1 = 43 - 0 = 43
<u>Finding</u><u> the</u><u> </u><u>second</u><u> </u><u>term </u><u>:</u>
Substituting n = 2 , we have,
→ T2 = 43 -3(2-1)
→ T2 = 43 -3*1
→ T2 = 43 -3 = 40
<u>Finding</u><u> </u><u>the </u><u>third </u><u>term</u><u> </u><u>:</u>
Substituting n = 3 , we have,
→ T3 = 43 -3(3-1)
→ T3 = 43 -3*2
→ T3 = 43 -6 = 37
<u>Finding</u><u> the</u><u> </u><u>fourth</u><u> </u><u>term </u><u>:</u>
→ T4 = 43 -3(4-1)
→ T4 = 43 -3*3
→ T4 = 43-9 = 34
<u>Hence</u><u> the</u><u> </u><u>first</u><u> </u><u>four</u><u> terms</u><u> of</u><u> </u><u>the</u><u> </u><u>sequence</u><u> </u><u>are </u><u>4</u><u>3</u><u> </u><u>,</u><u> </u><u>4</u><u>0</u><u> </u><u>,</u><u> </u><u>37</u><u> </u><u>and </u><u>34</u><u> </u><u>.</u>
<em>I </em><em>hope</em><em> this</em><em> helps</em><em> </em><em>.</em><em> </em><em>Let </em><em>me</em><em> know</em><em> if</em><em> you</em><em> </em><em>need </em><em>further</em><em> </em><em>clarification</em><em> </em><em>.</em>
Answer:
No solution
Step-by-step explanation:
2x - 8 + 3x > 5x - 4
2x + 3x - 8 > 5x - 4
5x - 8 > 5x - 4
-5x +8 > -5x +8
----------------------
0x > 4
This is no solution, as there is no 'x' value.
(0x just means there isn't anything left, I put that in order to show there wasn't anything.)