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Fiesta28 [93]
2 years ago
7

IF A, B, C are three mutually exclusive events with 1/3p(A)=2/3p(B)=1/6P(C).

Mathematics
1 answer:
Bas_tet [7]2 years ago
7 0
A=2(67.76).45 it’s ten divided by 8
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Which statement correctly finds the interquartile range for the set of data represented by the box plot?
gizmo_the_mogwai [7]

Answer:

<em>B. 11 - 6 = 5</em>

Step-by-step explanation:

Median: 9.5

Lower Quartile: 6

Upper Quartile: 11

Interquartile Range: upper quartile - lower quartile = answer

6 0
3 years ago
In the expression 14b what is the coefficient? *
Pachacha [2.7K]

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4 0
2 years ago
Is 3/4 greater than 7/8?
yKpoI14uk [10]
3/4 = (2*3) / (2* 4) = 6/8

7/8.

Is 3/4 greater than 7/8? 
Is like asking is 6/8 greater than 7/8?  Because 3/4 is equivalent to 6/8.

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3 0
3 years ago
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Are these ratios equivalent?
krek1111 [17]

Answer:

Yes

Step-by-step explanation:

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8 0
3 years ago
Can u please help me with this 2 problem please
Mice21 [21]
<h2>19.</h2><h3>Given</h3>
  • window width and height are in proportion to building width and height
  • window width and height are 11 in and 18 in, respectively
  • building height is 108 ft
<h3>Find</h3>
  • building width
<h3>Solution</h3>

The proportional relation can be written as

... (building width)/(building height) = (window width)/(window height)

Multiplying by (building height) gives

... (building width) = (building heigh) × (window width)/(window height)

... (building width) = 108 ft × (11 in)/(18 in)

... building width = 66 ft

<h2>21.</h2><h3>Given</h3>
  • map distance = 6.75 in
  • map scale = 1.5 in : 5 mi
<h3>Find</h3>
  • actual distance
<h3>Solution</h3>

The distances are in proportion, so

... (map distance) : (actual distance) = 1.5 in : 5 mi

Multiplying by (5 mi)/(1.5 in)×(actual distance), we have

... (5 mi)/(1.5 in)×(6.75 in) = (actual distance) = 22.5 mi

6 0
3 years ago
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