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anzhelika [568]
3 years ago
12

What is the equation of the parabola?

Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

y = -1/8 x² + 5

Step-by-step explanation:

Parabola opens vertically and vertex (h,k) = (0,5), pass point (4,3)

basic formula: y = a(x - h)² + k

y = a (x-0)² + 5

y = ax² + 5         pass (4,3)

3 = 16a + 5

a = (3-5)/16 = -1/8

equation: y = -1/8 x² + 5

check: pass another point (-4,3)

-1/8 * (-4)² + 5 = -2 + 5 = 3

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Answer:  B. H(t) = -6.9(t - 2.3)² + 112

<u>Step-by-step explanation:</u>

The vertex form of a quadratic equation is: y = a(x - h)² + k

where (h, k) is the vertex   ⇒    k is the maximum height

the distance traveled is when y = 0     ⇒    x=\sqrt{\dfrac{-k}{a}}+h

Given: H(t) = -7.1(t - 2.3)² + 98

maximum height (k) = 98 feet

distance traveled (x) = \sqrt{\dfrac{-98}{-7.1}}+2.3    = 6.02 seconds

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maximum height (k) = 112 feet

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B) H(t) = -6.9(t - 2.3)² + 112

maximum height (k) = 112 feet

distance traveled (x) = \sqrt{\dfrac{-112}{-6.9}}+2.3    = 6.33 seconds

C) H(t) = -6.9(t - 2.4)² + 95

maximum height (k) = 95 feet

This has a lower height than the given equation.

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maximum height (k) = 95 feet

This has a lower height than the given equation.

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