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taurus [48]
3 years ago
9

The length of Joseph’s rectangular poster is two times it’s width. If the perimeter is 24 inches, what is the area of the poster

?
Mathematics
1 answer:
leonid [27]3 years ago
6 0
Let's assign the width to a variable, with that variable being x. the length is two times the width, so it would be 2x. the perimeter of a rectangle is length + length + width + width, so you would add 2x + 2x + x + x = 24 inches. combine like terms (x) to get 6x = 24. divide both sides by 6 to get x = 4. so the width (x) is 4, and the length (2x) is 8. the area of a rectangle is length times width, so multiply 4 * 8. that would get you 32 inches^2.
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