Answer:
math is a difficult subject
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Answer:
Step-by-step explanation:
The lateral surface area is the product of half the circumference, and the slant height:
LA = πrh = π(11.4 cm)(23 cm) = 262.2π cm²
The total surface area adds the area of the base to that:
A = πr² +LA = π(11.4 cm)² +262.2π cm² = (129.96 +262.2)π cm²
A = 392.16π cm²
Answer: ![A^{-1}=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]](https://tex.z-dn.net/?f=A%5E%7B-1%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B3%7D%7B2%7D%26-%5Cfrac%7B1%7D%7B2%7D%5C%5C-2%261%5Cend%7Barray%7D%5Cright%5D)
<u>Step-by-step explanation:</u>
![\left[\begin{array}{cc}2&1\\4&3\end{array}\right]=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%261%5C%5C4%263%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
![\dfrac{1}{2}Row\ 1\rightarrow\left[\begin{array}{cc}1&\frac{1}{2}\\4&3\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7DRow%5C%201%5Crightarrow%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26%5Cfrac%7B1%7D%7B2%7D%5C%5C4%263%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B1%7D%7B2%7D%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
![Row\ 2 -4 \ Row\ 1\rightarrow \left[\begin{array}{cc}1&\frac{1}{2}\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\-2&1\end{array}\right]](https://tex.z-dn.net/?f=Row%5C%202%20-4%20%5C%20Row%5C%201%5Crightarrow%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26%5Cfrac%7B1%7D%7B2%7D%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B1%7D%7B2%7D%260%5C%5C-2%261%5Cend%7Barray%7D%5Cright%5D)
![Row\ 1-\dfrac{1}{2}\ Row\ 2 \rightarrow \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]](https://tex.z-dn.net/?f=Row%5C%201-%5Cdfrac%7B1%7D%7B2%7D%5C%20Row%5C%202%20%5Crightarrow%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B3%7D%7B2%7D%26-%5Cfrac%7B1%7D%7B2%7D%5C%5C-2%261%5Cend%7Barray%7D%5Cright%5D)
The formula of an area of a square:
a - a side
We have 
substitute:
Used:
Answer:
i can help with a littel bit of it
Step-by-step explanation:
1. answer
29±95‾‾‾√9
x
=
−
2
9
±
95
i
9
=−0.222222+1.08298
x
=
−
0.222222
+
1.08298
i
=−0.222222−1.08298
x
=
−
0.222222
−
1.08298
i
Find the Solution for:
92+4+11=0
9
x
2
+
4
x
+
11
=
0
using the Quadratic Formula where
a = 9, b = 4, and c = 11
=−±2−4‾‾‾‾‾‾‾‾√2
x
=
−
b
±
b
2
−
4
a
c
2
a
=−4±42−4(9)(11)‾‾‾‾‾‾‾‾‾‾‾‾√2(9)
x
=
−
4
±
4
2
−
4
(
9
)
(
11
)
2
(
9
)
=−4±16−396‾‾‾‾‾‾‾‾‾√18
x
=
−
4
±
16
−
396
18
=−4±−380‾‾‾‾‾√18
x
=
−
4
±
−
380
18
The discriminant 2−4<0
b
2
−
4
a
c
<
0
so, there are two complex roots.
Simplify the Radical:
=−4±295‾‾‾√18
x
=
−
4
±
2
95
i
18
=−418±295‾‾‾√18
x
=
−
4
18
±
2
95
i
18
Simplify fractions and/or signs:
=−29±95‾‾‾√9
x
=
−
2
9
±
95
i
9
which becomes
=−0.222222+1.08298
x
=
−
0.222222
+
1.08298
i
=−0.222222−1.08298
2. Answer:
=−38±895‾‾‾‾√40
x
=
−
3
8
±
895
i
40
=−0.375+0.747914
x
=
−
0.375
+
0.747914
i
=−0.375−0.747914
x
=
−
0.375
−
0.747914
i
3. Answer:
=0=−74
x
=
0
x
=
−
7
4
=0
x
=
0
=−1.75
Find the Solution for
82+14+0=0
8
x
2
+
14
x
+
0
=
0
using the Quadratic Formula where
a = 8, b = 14, and c = 0
=−±2−4‾‾‾‾‾‾‾‾√2
x
=
−
b
±
b
2
−
4
a
c
2
a
=−14±142−4(8)(0)‾‾‾‾‾‾‾‾‾‾‾‾√2(8)
x
=
−
14
±
14
2
−
4
(
8
)
(
0
)
2
(
8
)
=−14±196−0‾‾‾‾‾‾‾√16
x
=
−
14
±
196
−
0
16
=−14±196‾‾‾‾√16
x
=
−
14
±
196
16
The discriminant 2−4>0
b
2
−
4
a
c
>
0
so, there are two real roots.
Simplify the Radical:
=−14±1416
x
=
−
14
±
14
16
=016=−2816
x
=
0
16
x
=
−
28
16
=0=−74
x
=
0
x
=
−
7
4
which becomes
=0
x
=
0
=−1.75
i hope this helps
