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inysia [295]
3 years ago
6

Please help will mark brainliest

Mathematics
2 answers:
Sever21 [200]3 years ago
8 0
The answer is A because its a 90 degree angle and you need to add both sides to get the answer
kolbaska11 [484]3 years ago
3 0

It is A due to the fact that the over all angle is 90 degrease.

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Divide.<br> (8x^3+ 31x^2+ 6x +40) + (2x+8)
aksik [14]

Answer:

divide them by what?

or fivide it with eachother?

7 0
3 years ago
# 15. Q. Find the area of the trapezoid
harina [27]
Answer:
219.96 yd²

Explanation:
The area of the trapezoid can be calculated using the following rule:
Area of trapezoid = \frac{b1 + b2}{2} * h
where:
b1 is the length of the first base
b2 is the length of the second base
h is the height

Now, in the given we have:
b1 = 15.8 yd
b2 = 21.8 yd
h = 11.7 yd

Substitute with the givens in the above equation to get the area as follows:
area = \frac{15.8 + 21.8}{2}  * 11.7 = 219.96 yd^2

Hope this helps :)
7 0
3 years ago
Sarah has a $2000 bond with a 7% coupon. How much interest will Sarah receive for this bond every 6 months?
Leno4ka [110]
Per year 7% for $2000 bond. It will be $140 per year.

Then per 6 months, it will be $70.

so, answer is B.
8 0
3 years ago
Read 2 more answers
What do you do when you multiply the ratios
goblinko [34]
Multiplying ratios is just like multiplying fractions. 

Ex: 

5:10 = 5/10 

5:10 · 2:20 = 5/10·2/20. 

keep 5/10, 
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8 0
3 years ago
On a particular map, 3 inches on the map equates to 10 miles in real life. If you know that the real-life distance between two b
Yakvenalex [24]

Answer:

15\dfrac{39}{40} $ inches

Step-by-step explanation:

On the map, 3 inches = 10 miles in real life.

Therefore:

10 miles: 3 Inches

1$ miles rep $ \dfrac{3}{10}$ inches

If the real-life distance between two buildings is 53.25 miles

Distance on the map

\dfrac{3}{10}$ X 53.25 inches\\=15.975 inches

=15\dfrac{39}{40} $ inches

The distance between the two buildings on the map is therefore: 15\dfrac{39}{40} $ inches

3 0
3 years ago
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