Answer:
i am just a little confused but so far its a yes
Step-by-step explanation:
Answer: q = -13
Step-by-step explanation:
(q+5)/4 = -2 first you multiply 4 to remove denominators
(q+5) = -8 then subtract 5
q = -13
<h3>
Answer: Choice A) 0.20</h3>
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Explanation:
Let's say there are 1000 students. The students must take math, science or they can take both simultaneously.
- 65% of them are in math. So there are 0.65*1000 = 650 math students.
- 43% are in science, leading to 0.43*1000 = 430 science students.
- 13% are in both so we have 0.13*1000 = 130 students who are in both.
Now onto the sentence that says "Suppose a high school student who is enrolled in a math class is selected at random"
This means we only focus on the 650 math students and ignore the 1000-650 = 350 students who aren't in math.
Of those 650 math students, 130 are also in science (since 130 are in both classes).
The probability we're after is therefore 130/650 = 0.20
Answer:
The value is 0.82
Step-by-step explanation:
