I dont think so but to justify quads means four and the is no sign of x to the fourth power or y to the fourth power ect.
for the lines k (x) = (- 9 / 5) x + (5 / 2) and h (x) = (2 / 5) x - (7 / 6), the solution for x will be 5 / 3 and y will be - 1 / 2.
We are given the two lines:
k (x) = (- 9 / 5) x + (5 / 2)
h (x) = (2 / 5) x - (7 / 6)
At the intersection of the two lines, we get that:
(- 9 / 5) x + (5 / 2) = (2 / 5) x - (7 / 6)
(2 / 5) x + (9 / 5) x = (5 / 2) + (7 / 6)
(11 / 5) x = 11 / 3
3 x = 5
x = 5 / 3
y = (2 / 5) (5 / 3) - (7 / 6)
y = 2 / 3 - 7 / 6
y = - 1 / 2
Therefore, we get that, for the lines k (x) = (- 9 / 5) x + (5 / 2) and h (x) = (2 / 5) x - (7 / 6), the solution for x will be 5 / 3 and y will be - 1 / 2.
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2 and 4 are both correct statements.
Answer:
3.418 grams
Step-by-step explanation:
please mark me as brainliest
Answer:
(15, 12)
Step-by-step explanation:
Let's generate two systems of equations that fit this scenario.
Number of trips to the airport = x
Number of trips from the airport = y
Total number of trips to and from the airport = 27
Thus:
=> equation 1.
Total price for trips to the Airport = 14*x = 14x
Total price of trips from the airport = 7*y = 7y
Total collected for the day = $294
Thus:
=> equation 2.
Multiply equation 1 by 7, and multiply equation 2 by 1 to make both equations equivalent.
7 ×
1 ×
Thus:
=> equation 3
=> equation 4
Subtract equation 4 from equation 3
-7x = -105
Divide both sides by -7
x = 15
Substitute x = 15 in equation 1
Subtract both sides by 15
The ordered pair would be (15, 12)
