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Assoli18 [71]
3 years ago
14

What is the standard form of 8 hundreds + 2 hundreds

Mathematics
1 answer:
ankoles [38]3 years ago
8 0
Seeing as standard form is the typical way we see numbers, we can look at this problem as 800+200. Therefore, the correct answer would be 1,000.
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Is this table proportional or non-proportional?
Jlenok [28]

Answer:

Proportional

Step-by-step explanation:

Proportional functions can be written as y=kx, where k is some constant of proportionality. Plugging in (x,y) pair into this function will yield a constant of proportionally of k=\frac{3}{2} and since this constant is maintained through all the coordinate pairs in the table, the table is proportional.

3 0
3 years ago
What are the amplitude, period, phase shift, and midline of f(x) = 2 sin(x + π) − 4?
MrRissso [65]

\bf ~~~~~~~~~~~~\textit{function transformations} \\\\\\ % templates f(x)=Asin(Bx+C)+D \\\\ f(x)=Acos(Bx+C)+D\\\\ f(x)=Atan(Bx+C)+D \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \bullet \textit{ stretches or shrinks}\\ ~~~~~~\textit{horizontally by amplitude } A\cdot B\\\\ \bullet \textit{ flips it upside-down if }A\textit{ is negative}\\ ~~~~~~\textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }B\textit{ is negative}\\ ~~~~~~\textit{reflection over the y-axis}


\bf \bullet \textit{ horizontal shift by }\frac{C}{B}\\ ~~~~~~if\ \frac{C}{B}\textit{ is negative, to the right}\\\\ ~~~~~~if\ \frac{C}{B}\textit{ is positive, to the left}\\\\ \bullet \textit{vertical shift by }D\\ ~~~~~~if\ D\textit{ is negative, downwards}\\\\ ~~~~~~if\ D\textit{ is positive, upwards}\\\\ \bullet \textit{function period or frequency}\\ ~~~~~~\frac{2\pi }{B}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\ ~~~~~~\frac{\pi }{B}\ for\ tan(\theta),\ cot(\theta)


with that template in mind, let's take a peek


\bf f(x)=2sin(x+\pi )-4\implies f(x)=\stackrel{A}{2}sin(\stackrel{B}{1}x\stackrel{C}{+\pi })\stackrel{D}{-4} \\\\[-0.35em] ~\dotfill\\\\ \textit{Amplitude}\implies 2 \\\\\\ \stackrel{phase}{\textit{Horizontal Shift}}\implies \cfrac{C}{B}\implies \cfrac{+\pi }{1}\implies +\pi \impliedby \pi \textit{ units to the left} \\\\\\ \textit{Period}\implies \cfrac{2\pi }{B}\implies \cfrac{2\pi }{1}\implies 2\pi \\\\\\ \textit{Vertical Shift}\implies D\implies -4\impliedby \textit{4 units downwards}


now, the midline for the parent function of sin(x) is simply the x-axis, namely y = 0.

this shifted/transformed version of it, has a vertical shift of 4 units down, so the midline moved from y = 0, to y = -4.

6 0
3 years ago
John bought three thermos flask at a total of st 1080 he later sold at 400 each what was his percentage ​
trasher [3.6K]

Answer:

\boxed{ \bold{ \boxed{ \sf {11.11\%}}}}

Step-by-step explanation:

Given,

Cost price of three thermos flask = 1080

Selling price of each thermos flask = 400

<u>Finding </u><u>the </u><u>selling </u><u>price </u><u>of </u><u>three </u><u>thermos </u><u>flask</u>

Since, the cost of 3 thermos flask is more than that of 1 thermos flask. So, the cost of 1 thermos flask is multiplied by 3 ( i.e 400 × 3 = 1200 )

Here, the selling price is greater than cost price.

So, there is profit.

And we know that,

\sf{profit = sp \:  -  \: cp}

⇒\sf{1200 - 1080}

⇒\sf{120}

Profit amount = 120

<u>Finding </u><u>the </u><u>profit </u><u>percentage</u>

\sf{profit\% \:  =  \frac{profit}{cp}  \times 100 \%}

⇒\sf{ \frac{120}{1080 } \times 100\%}

⇒\sf{11.11\%}

Hope I helped!

Best regards!!

6 0
2 years ago
What is the factorization of 121b^4-49
Nezavi [6.7K]

121^4-49

(11^2+7)(11^2-7) 1. 121. 49

11. × 11. 7 × 7

4 0
3 years ago
In standard notation 208.06 is written as
andreyandreev [35.5K]

Answer:

2.0806 × 10²

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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