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insens350 [35]
2 years ago
6

What is 220086*567890

Mathematics
1 answer:
charle [14.2K]2 years ago
8 0

Answer:

124984638540

Step-by-step explanation:

just use a calculator

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Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
Alik [6]

Answer:

P(X

And for this case we can use the cumulative distribution function given by:

P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b

And using this formula we have this:

P(X

Then we can conclude that the probability that your bid will be accepted would be 0.41

Step-by-step explanation:

Let X the random variable of interest "the bid offered" and we know that the distribution for this random variable is given by:

X \sim Unif( a= 10100, b =14700)

If your offer is accepted is because your bid is higher than the others. And we want to find the following probability:

P(X

And for this case we can use the cumulative distribution function given by:

P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b

And using this formula we have this:

P(X

Then we can conclude that the probability that your bid will be accepted would be 0.41

8 0
2 years ago
Kim works 4 hours more each day than jill does, and jack works 2 hours less each day
Nadusha1986 [10]
Where's the rest of the question
6 0
3 years ago
Read 2 more answers
Write an equation of the perpendicular bisector of the segment with endpoints M(1,5) and N(7,−1).
solong [7]

Answer:

Step-by-step explanation:

find the perpendicular bisector of a line segment with endpoints  

(ii) Find a point on the perpendicular bisector (the midpoint of the given line segment) using the midpoint formula:

( x 3 , y 3 ) = ( x 1 + x 2 2 , y 1 + y 2 2 )

6 0
3 years ago
The length of a rectangle is 4 m less than the diagonal and the width is 5 m less than the diagonal. If the area is 82 m^2, how
nikklg [1K]

I hate rounding.

Let's call the diagonal x.  It's the hypotenuse of the right triangle whose legs are the rectangle sides.

According to the problem we have a length x-4 and a width x-5 and an area

82 = (x-4)(x-5)

82 = x^2 - 9x + 20

0 = x^2 - 9x - 62

That one doesn't seem to factor so we go to the quadratic formula

x = \frac 1 2(9 \pm \sqrt{9^2-4(62)}) = \frac 1 2(9 \pm \sqrt{329})

Only the positive value makes any sense for this problem, so we conclude

x = \frac 1 2(9 \pm \sqrt{329})

That's the exact answer.  Did I mention I hate rounding?  That's about

x = 13.6 meters

Answer: 13.6

----------

It's not clear to me this problem is consistent.  By the Pythagorean Theorem the diagonal satisfies

x^2 = (x-4)^2 + (x-5)^2

which works out to

x=9 \pm 2\sqrt{10}

That's not consistent with the first answer; this problem really has no solution.  Tell your teacher to get better material.

5 0
2 years ago
What is the range of the function f(x) = 4x + 9, given the domain D = {-4, -2, 0, 2}? please help
neonofarm [45]
Since this is a linear function, filling in the minimum and maximum of the domain is sufficient.

f(-4) = -16 + 9 = -7
f(2)= 8 + 9 = 17

So the range of the function (given the domain) :
R = {-7, 17}
8 0
3 years ago
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