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Sholpan [36]
2 years ago
5

How do you solve the equation F = 9/5(K - 273.15) + 32 when you're solving for K?

Mathematics
1 answer:
Mumz [18]2 years ago
7 0

\displaystyle\\Answer:\ K=\frac{5}{9}(F-32^0)+273.15^0

Step-by-step explanation:

\displaystyle\\F=\frac{9}{5} (K-273.15)+32\\F-32=\frac{9}{5} (K-273.15)+32-32\\F-32=\frac{9}{5} (k-273.15)\\Multiply\  both\  parts\  of\  the\  equation\  by\ \frac{5}{9} \\(\frac{5}{9})(F-32)=\frac{9}{5}  (K-273.15)(\frac{5}{9} )\\\\\frac{5}{9} (F-32)=K-273.15\\\\\frac{5}{9} (F-32)+273.15=K-273.15+273.15\\\\\frac{5}{9} (F-32)+273.15=K

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What are the coordinates of the vertex for the function shown below ?
Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

We can answer this in two ways:  Differentiation and Graphing.

<u>Differentitate:</u>

The first derivative of a function yields a function that provides the slope for any point on the line of the original function.  The slope of a vertex is zero, so we can set the first derivative to 0 and solve for x.

f(x) = 3(x-1)^2 + 4

f(x) = 3(x-1)(x-1) + 4

f(x) = 3(x^2 - 2x + 1) + 4

f(x) = 3x^2 - 6x + 7

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0 = 6x -6

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The value of y when x=1 in the original equation is:

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y = 4

The vertex is (1,4)

<u>Graph:</u>

You can use DESMOS to plot the function.  The result is attached.  Look for the vertex and read the coordinates.  (1,4) seems to work.

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3 years ago
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