Answer:
Semi-annually: A = $24 178.51
Quarterly: A = $24 205.73
Monthly: A = $24 224.13
Step-by-step explanation:
The formula for compound interest is
A = P(1 + r)ⁿ
A. Compounded semi-annually
Data:
P = $20 000
APR = 4.8 %
t = 4 yr
Calculations:
n = 4 × 2 = 8
r = 0.048/2 = 0.024
A = 20 000(1+ 0.024)⁸
= 20 000 × 1.024⁸
= 20 000 × 1.208 926
= $24 178.51
B. Compounded Quarterly
n = 4 × 4 = 16
r = 0.048/4 = 0.012
A = 20 000(1+ 0.012)¹⁶
= 20 000 × 1.012¹⁶
= 20 000 × 1.210 286
= $24 205.73
C. Compounded monthly
n = 4 × 12 = 48
r = 0.048/12 = 0.004
A = 20 000(1+ 0.004)⁴⁸
= 20 000 × 1.004⁴⁸
= 20 000 × 1.211 207
= $24 224.13
Answer:
(8, 11 )
Step-by-step explanation:
Given the 2 equations
2x + 2y = 38 → (1)
y = x + 3 → (2)
Substitute y = x + 3 into (1)
2x + 2(x + 3) = 38 ← distribute and simplify left side
2x + 2x + 6 = 38
4x + 6 = 38 ( subtract 6 from both sides )
4x = 32 ( divide both sides by 4 )
x = 8
Substitute x = 8 into (2) for corresponding value of y
y = 8 + 3 = 11
Solution is (8, 11 )
Please see attached image for the graph.
a.
Yes, it is mathematically possible because the
degree of vertices for P=3, T=3, M=2, C=4, and R=2 and in Euler’s theorem, the
graph has to be connected, which in this case it is and the number of vertices
in the graph whose vertices is odd, is 0 or 2. And in this case, we have 2 that
have a degree of vertices that are odd, therefore mathematically this is
possible for the driver. The route would be P > R > C > M > T > C
> P > T.
b.
<span>It is mathematically possible. The router would be P
> C > R > T > M > C > T. Essentially, you travel each road
once.
</span>
c.
The driver would use a Hamiltonian circuit. The route
would be J > R > A > C > V > M > T > P > J.
Answer:
x = -3
Step-by-step explanation:
7x - 3 = -24 (Given)
7x - 3 + 3 = -24 + 3 (Added 3 on both sides by using the addition property of equality)
7x = -21 (Simplified)
7x/7 = -21/7 (Divided 7 on both sides by using the division property of equality)
x = -3 (Simplified)
Therefore, x = -3.
