Answer:
Area of the shaded region = 23.33 in²
Step-by-step explanation:
Area of a sector = ![\frac{\theta}{360}(\pi r^{2})](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctheta%7D%7B360%7D%28%5Cpi%20r%5E%7B2%7D%29)
Where θ = Central angle subtended by an arc
r = radius of the circle
Area of the sector BCD = ![\frac{60}{360}(\pi) (10^{2})](https://tex.z-dn.net/?f=%5Cfrac%7B60%7D%7B360%7D%28%5Cpi%29%20%2810%5E%7B2%7D%29)
= 52.36 in²
Area of equilateral triangle BCD = ![\frac{\sqrt{3} }{4}(\text{Side})^2](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B4%7D%28%5Ctext%7BSide%7D%29%5E2)
= ![\frac{\sqrt{3} }{4}(10)^2](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B4%7D%2810%29%5E2)
=
in²
= 43.30 in²
Area of the shaded portion in ΔBCD = 52.36 - 43.3
= 9.06 in²
Area of sector CAD = ![\frac{90}{360}(\pi)(\sqrt{50})^2](https://tex.z-dn.net/?f=%5Cfrac%7B90%7D%7B360%7D%28%5Cpi%29%28%5Csqrt%7B50%7D%29%5E2)
= 39.27 in²
Area of right triangle CAD = ![\frac{1}{2}(\text{Base})(\text{Height})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BBase%7D%29%28%5Ctext%7BHeight%7D%29)
= ![\frac{1}{2}(\text{AC})(\text{AD})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BAC%7D%29%28%5Ctext%7BAD%7D%29)
=
= 25 in²
Area of the shaded part in the ΔACD = 39.27 - 25
= 14.27 in²
Area of the shaded part of the figure = 9.06 + 14.27
= 23.33 in²
Answer:
Since we know that ABCD ~ EFGH, we have the ratios:
EF/AB = GH/CD
=> 0.4/1.2 = x/1.8
=> x = (1.8 . 0.4)/1.2 = 0.6
So x = 0.6
Answer:
25 Balls
Step-by-step explanation:
It is 8.525. what u do is 21÷40 and get .525 and then u add the 8 in the front and get 8.525
Answer:
26
Step-by-step explanation:
Distance = (x2 - x1) ² + (y2 - y1)²
Distance = ( 3-4)² + (-2-3)²
Distance = 26