30 + 0.25m > 40 + 0.10m
0.25m - 0.10m > 40 - 30
0.15m > 10
m > 10/0.15
m > 67 miles.....u would have to drive 68 or more miles for the second company to be less expensive
Answer:
Given 7b²-21b-273=7, the solutions are x1 = 8 and x2 = -5.
Step-by-step explanation:
Given 7b²-21b-273=7, first you need to equal zero. So
7b²-21b-273-7=0 ⇒ 7b²-21b-280 = 0
The secon step is to find the solutions applying Bhaskara´s formula x = (-b ± √(b²-4×a×c))/2×a
Where a=7, b= -21 and c= -280
After you identified each term, you have to replace it on the formula so....
x = (21 ± √(21² - 4×7×(-280)))/2×7 ⇒ x = (21 ± √(441 + 7840))/14 ⇒ x = (21 ± √8281)/14
Then you will obtain two values for x, called x1 = 8 and x2=-5.
A plane's<span> engines are designed to move it forward at high speed. That makes air flow rapidly over the wings, which throw the air down toward the ground, generating an upward force called lift that overcomes the </span>plane's<span> weight and holds it in the sky. ... The wings force the air downward and that pushes the </span>plane<span> upward.</span>
I personally think its 18, please tell me what i did wrong <span />
Answer:
x = 4
2x + 1 - 1 = 9 - 1
2x = 8
2x/2 = 8/2
x = 4
Step-by-step explanation:
