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kifflom [539]
3 years ago
9

Which clipboard (A, B, or C) represents a 270 degree counter- clockwise rotation?

Mathematics
2 answers:
nignag [31]3 years ago
5 0

Answer: C

Step-by-step explanation:

Because if you look at the star then it will show you how it rotated.

Anuta_ua [19.1K]3 years ago
3 0

Answer: C

Step-by-step explanation: im not 100% sure but i think thats it

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Factor completely. x2−5x+18x2-5x+18
dimulka [17.4K]

Answer:

The answer is (x - 9) what y'all doinggg!!!!!!!!???

4 0
4 years ago
In △ABC, m∠A=57°, m∠B=37°, and a=11. Find c to the nearest tenth.
kykrilka [37]

Answer:

c=13.1\ units

Step-by-step explanation:

step 1

Find the measure of angle C

Remember that the sum of the interior angles of a triangle must be equal to 180 degrees

so

A+B+C=180°

we have

A=57°

B=37°

substitute

57°+37°+C=180°

94°+C=180°

C=180°-94°=86°

step 2

Find the measure of side c

Applying the law of sines

\frac{a}{sin(A)}=\frac{c}{sin(C)}

substitute

\frac{11}{sin(57\°)}=\frac{c}{sin(86\°)}

c=\frac{11}{sin(57\°)}sin(86\°)

c=13.1\ units

8 0
3 years ago
Help me please akdjehwlsjn
Varvara68 [4.7K]

Answer:

3/5

Step-by-step explanation:

8 0
3 years ago
Write 35 weeks as a number of years
arsen [322]
Since there are 52 weeks in a year, we can display this as a fraction.

So,
35/52

Hope this helps!
5 0
3 years ago
This is my last question please help asap!!
Ivanshal [37]

The average rate of change of function g(x)=5(2)^{x} from x = 3 to x = 4 is 4 times that from x = 1 to x = 2.

The correct option is (A).

What is the average rate of change of a function?

The average rate at which one quantity changes in relation to another's change is referred to as the average rate of change function.

Using function notation, we can define the Average Rate of Change of a function f from a to b as:

                                     rate(m) = \frac{f(b)-f(a)}{b-a}

The given function is  g(x) = 5(2)^{x},

Now calculating the average rate of change of function from x = 1 to x = 2.

                               m = \frac{g(b)-g(a)}{b-a}\\ m = \frac{g(2)-g(1)}{2-1}\\\\m=\frac{5(2)^{2}-5(2)^1}{2-1}\\ m=\frac{10}{1} \\m=10

Now, calculate the average rate of change of function from x = 3 to x = 4.

                                 m = \frac{g(b)-g(a)}{b-a}\\ m = \frac{g(4)-g(3)}{4-3}\\\\m=\frac{5(2)^{4}-5(2)^3}{4-3}\\ m=\frac{40}{1} \\m=40

The jump from m = 10 to m = 40 is "times 4".

So option (A) is correct.

Hence, The average rate of change of function g(x)=5(2)^{x} from x = 3 to x = 4 is 4 times that from x = 1 to x = 2.

To learn more about the average rate of change of function, visit:

brainly.com/question/24313700

#SPJ1  

7 0
1 year ago
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