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g100num [7]
3 years ago
6

Geneva rode her bike a total of 2 1/2 miles from her house to school. First she rode 4/5 mile from her house to the park. Then s

he rode 1/5 mile from the park to her friend’s house. Finally she rode the rest of the way to her school. How many miles did she ride from her friend's house to school?
Mathematics
1 answer:
Sonja [21]3 years ago
8 0
Add 4/5 and 1/5 to make 5/5 or 1 mile the subtract 1 from 2 1/2 to equal 1 1/2 miles
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poor ixl 78+78 i think because it had 78 and she drove 78

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Find the values of z and y pls :)
stellarik [79]
Measure of z is 116°.The measure of y is 48°.Hope this helps.
4 0
3 years ago
On a particular airline, bags checked in must weigh less than 50 pounds. Betty packed 32 pounds of clothes and five gifts that w
andreev551 [17]

Answer:

5x + 32 < 50

Step-by-step explanation:

On a particular airline, bags checked in must weigh less than 50 pounds. Betty packed 32 pounds of clothes and five gifts that weigh the same amount.

If each gift weighs w pounds, then the weight of five gifts will be 5w pounds and an additional 32 pounds of clothes will make it total (32 + 5w) pounds.  

Now, this total weight has to be less than 50 pounds.

Therefore, the inequality equation that can be used to find the possible weight of each gift, w is  

5x + 32 < 50 (Answer)

3 0
3 years ago
A diagnostic test for a disease is such that it (correctly) detects the disease in 90% of the individuals who actually have the
Ne4ueva [31]

Answer:

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test positive

Event B: Has the disease

Probability of a positive test:

90% of 3%(has the disease).

1 - 0.9 = 0.1 = 10% of 97%(does not have the disease). So

P(A) = 0.90*0.03 + 0.1*0.97 = 0.124

Intersection of A and B:

Positive test and has the disease, so 90% of 3%

P(A \cap B) = 0.9*0.03 = 0.027

What is the conditional probability that she does, in fact, have the disease

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.027}{0.124} = 0.2177

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

3 0
3 years ago
2. Construct Arguments An ostrich runs 6 miles
Alekssandra [29.7K]

Answer:

<u>At a constant speed of 0.5 miles per minute, the ostrich can run 20 miles in 40 minutes. The unit rate is 0.5 miles per minute.</u>

Step-by-step explanation:

Distance run by the ostrich = 6 miles

Time the ostrich takes to run this distance = 12 minutes

Speed of the ostrich = Distance / Time

Speed of the ostrich = 6 miles / 12 minutes = 0.5 miles per minute

How far the  ostrich could run in 40 minutes?

If the ostrich run 0.5 miles per minute, this is the formula:

Speed of the ostrich * 40 minutes = Distance

0.5 miles/minute * 40 minutes = 20 miles (Minutes is simplified in the numerator and the denominator on the left side)

<u>At a constant speed of 0.5 miles per minute, the ostrich can run 20 miles in 40 minutes. The unit rate is 0.5 miles per minute.</u>

6 0
3 years ago
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