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3 years ago

9

Alan is modeling 2.65 divided by 5. How should he exchange the place-value blocks so he can make 5 equal shares? Please explain

how you found your answer too.

1 answer:

valkas [14]3 years ago

8 0

Your answer is to the question is 0.53

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3 years ago

Suppose that 10% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to

balandron [24]

Answer:

0.9905,0.9837,0.8066

Step-by-step explanation:

Given that 10% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to be scrapped).

Each shaft is independent of the other and probability for non conforming is the same for each trial.

Hence X the among these that are nonconforming and can be reworked. is Bin with n =200 and p = 0.10

a) $P(X\leq 30) = 0.9905$

b) $P(X$

c) $P(15\leq x\leq 25)\\= F(25)-F(14)\\= 0.8995-0.0929\\= 0.8066$

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3 years ago