The complex solution of a quadratic equation are (- 2 + i ) and
(- 2 - i ).
What is Quadratic equation?
An algebraic equation of the second degree is called a quadratic equation.
Given that;
A quadratic equation is;
3x² = -12x - 15
Now, The equation is written as;
3x² + 12x + 15 = 0
Take 3 common, we get;
3 (x² + 4x + 5) = 0
x² + 4x + 5 = 0
Factorize the equation by using Sridharacharya Formula;
x = - 4 ± √4² - 4*1*5 / 2*1
x = -4 ± √16 - 20 / 2
x = - 4 ± √-4 / 2
Since, √-1 = i
x = -4 ± 2i / 2
x = - 2 ± i
It gives two values of x as;
x = - 2 + i
And, x = - 2 - i
Hence, The complex solution of a quadratic equation are (- 2 + i ) and
(- 2 - i ).
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Answer:
Step-by-step explanation:
Domain is the x values. The interval of x-values that the function encompasses are from 0 inclusive to 7 exclusive. In interval notation that is [0, 7). The range is the y values. The interval of y-values that the function encompasses are from what looks like -2 to 4. In interval notation that is [-2, 4]. The domain goes from the lowest x-value to the highest; the range goes from the lowest y-value to the highest.
Answer:
567 Miles
Step-by-step explanation:
Step-by-step explanation:
Given problem is to find nearest number,
= 8888888/2915
quotient = 3049
remainder= 1053
Now, 2915-1053 = 1862
8888888+1862 = 8890750
8888888-1053 = 8887835
Two numbers nearest to 8888888 which are exactly divisible by 2915 is 8887835 and 8890750
Answer:
(x - 6) meters
Step-by-step explanation:
x² - 12x + 36
x² - 2(x)(6) + 6²
(x - 6)² = side²
side = x - 6