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2 years ago

Solve question 20 (a) and (b)

Mathematics

1 answer:

RUDIKE [14]2 years ago

5 0

Answer:

You first have to read on the coordinates where the curve and the straight line meet or cuts across

a.) 53

b.) 13

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Which equation is true for the value a = 7?

professor190 [17]

THE first option is correct

7 0

3 years ago

Read 2 more answers

Write the equation for Chelsea's graph in

xeze [42]

Answer:

$y=-4x+16$ .

Step-by-step explanation:

From the given graph it is clear that the y-intercept is 16.

The line passes through (-2,24) and (2,8). So, slope of line is

$Slope=\dfrac{y_2-y_1}{x_2-x_1}$

$Slope=\dfrac{8-24}{2-(-2)}$

$Slope=\dfrac{-16}{4}$

$Slope=-4$

Slope intercept form of a line is

$y=mx+b$

where, m is slope and b is y-intercept.

Substitute m=-4 and b=16 in the above equation.

$y=(-4)x+(16)$

$y=-4x+16$

Therefore, the required equation is $y=-4x+16$ .

6 0

3 years ago

The Tour de France is a bike race around the country of France. The bike race is a three week race that covers approximately 2,2

valentinak56 [21]

Answer:

Approximately 54.54% of race happened in the first week.

Step-by-step explanation:

We are given the following in the question:

Length of bike race in three weeks = 2,200 miles

Race covered in first week = 1,200 miles

Percentage of race covered in first week =

$=\dfrac{\text{Race covered in first week}}{\text{Total length of race}}\times 100\%\\\\=\dfrac{1200}{2200}\times 100\%\\\\=54.54\%$

Thus, approximately 54.54% of race happened in the first week.

4 0

3 years ago

The answer to this problem?

LenaWriter [7]

The simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

<h3>How to simplify the expression?</h3>

The expression is given as:

$\sqrt{\frac{162x^9}{2x^{27}}}$

Divide 162 and 2 by 2

$\sqrt{\frac{81x^9}{x^{27}}}$

Take the square root of 81

$9\sqrt{\frac{x^9}{x^{27}}}$

Apply the quotient rule of indices

$9\sqrt{\frac{1}{x^{27-9}}}$

Evaluate the difference

$9\sqrt{\frac{1}{x^{18}}}$

Take the square root of x^18

$\frac{9}{x^9}$

Hence, the simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

Solve question 20 (a) and (b)​

Solve question 20 (a) and (b)