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PtichkaEL [24]
3 years ago
9

in a lecture hall at a collage, the number of seats per row increased at a constand rate. The professor counts 21 seats in row 3

and 33 seats in row 7. How many sets are there in row 18?
Mathematics
1 answer:
Allushta [10]3 years ago
7 0

Answer:

  66 seats

Step-by-step explanation:

The rate of increase is ...

  (change in seats)/(change in rows) = (33 -21)/(7 -3) = 12/4 = 3 . . . seats/row

Then row 18 will have (18-3)·3 = 45 more seats than row 3, hence ...

  21 + 45 = 66 . . . . seats in row 18

_____

An explicit formula for the number of seats can be written as ...

  s = 21 +3(n-3) = 12 +3n

For n=18, this is ...

 s = 12 + 3(18) = 12 +54 = 66 . . . seats in row 18

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9514 1404 393

Answer:

  y = -3x^2 +3x +6

Step-by-step explanation:

For roots p and q, the equation can be written as ...

  y = a(x -p)(x -q)

The value of 'a' must be determined so that the product <em>apq</em> is equal to the y-intercept. One could say that the formula is ...

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  y = -3(x^2 -x -2) . . . . . simplifying a bit

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