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7nadin3 [17]
3 years ago
8

Question 2: Sum of consecutive odd View Past Answers No past answers. Write a program which asks user to enter an integer n, cal

culates the total sum of the consecutive ODD integers from 1 to n (inclusive of n if n is odd) and store in the variable called sum calculates the average value of the consecutive ODD integers from 1 to n and store in the variable called average prints the value of sum and average For example if n = 7, the program will compute 1+3+5+7, sum = 16, average = 4 if n = 6, the program will compute 1+3+5, sum = 9, average = 3
Pls help ya thx(btw this is python)
Computers and Technology
2 answers:
Vikentia [17]3 years ago
6 0

Answer:

number = int(input("Enter number ") )

sum = 0

count = 0

for x in range(1, number+1, 2):

 sum += x

 count += 1

average = sum/count

print("sum = %d"% sum)

print("average = %d"% average)

The range() function conveniently lets you enumerate all odd values from 1 to your number.

svp [43]3 years ago
4 0
Answer:

Step-by-step Explanation:
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It is true that in the array implementation of a queue, the pop operation is most efficient if the front of the queue is fixed at index position. The correct option is a.

<h3>What is pop operation? </h3>

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A push operation decrements the pointer before copying data to the stack; a pop operation copies data from the stack before incrementing the pointer.

The pop operation in an array implementation of a queue is most efficient if the queue's front is fixed at index position.

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