Local(L) = 1 x (15.99)
Online(O) = (1 x 13.99) + 6
So use that equation until you find the same number.
L1=15.99
O1=19.99
L2=31.98
O2=33.98
L3=47.97
O3=47.97
And your answer will be three from local and three from online.
Answer:
<h3>I THINK ITS • (4X2+32X+64-π(x2+2x+1))</h3>
Step-by-step explanation:
i hope it helps :)
Answer:
maybe 180
Step-by-step explanation:
Answer:
1) the signs of the numbers is not in standard form
2) always make sure that the signs of the two equations is standarised and then solve
please follow me
Answer:
a) cos(α+β) ≈ 0.8784
b) sin(β -α) ≈ -0.2724
Step-by-step explanation:
There are a couple of ways to go at these. One is to use the sum and difference formulas for the cosine and sine functions. To do that, you need to find the sine for the angle whose cosine is given, and vice versa.
Another approach is to use the inverse trig functions to find the angles α and β, then combine those angles and find find the desired function of the combination.
For the first problem, we'll do it the first way:
sin(α) = √(1 -cos²(α)) = √(1 -.926²) = √0.142524 ≈ 0.377524
cos(β) = √(1 -sin²(β)) = √(1 -.111²) ≈ 0.993820
__
a) cos(α+β) = cos(α)cos(β) -sin(α)sin(β)
= 0.926×0.993820 -0.377524×0.111
cos(α+β) ≈ 0.8784
__
b) sin(β -α) = sin(arcsin(0.111) -arccos(0.926)) ≈ sin(6.3730° -22.1804°)
= sin(-15.8074°)
sin(β -α) ≈ -0.2724
