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Airida [17]
3 years ago
6

Please answer! (1) what mistake was made? (2) what suggestion could help avoid that?

Mathematics
1 answer:
AveGali [126]3 years ago
3 0

Answer:

1) the signs of the numbers is not in standard form

2) always make sure that the signs of the two equations is standarised and then solve

please follow me

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50 POINTS PLEASE HELP
alexdok [17]

I am more than happy to help but i need you to tell me the dropbox options please :)


If they are 1,2 and 3 in the dropbox then:

1) would be 1

2) would be 3

3) would be 2

8 0
3 years ago
Read 2 more answers
Please answer this it would be very helpful if you did.
Dmitriy789 [7]

Answer:

See below ↓↓↓

Step-by-step explanation:

<u>Probability of getting heads</u>

  • Outcome (head) = 1
  • Total outcomes = 2
  • P (head) = <u>1/2</u>

<u></u>

<u>Probability of getting an odd number</u>

  • Outcome (odd) = {1, 3, 5} = 3
  • Total outcomes = 6
  • P (odd) = 3/6 = <u>1/2</u>

<u></u>

The outcomes are equally likely because the probabiity of each outcome is the same.

5 0
2 years ago
Considere a função de oferta como sendo y= 5x - 1/2 e a função de demanda como sendo y= -7x + 47/2 , onde x é a quantidade e y é
swat32

A) Temos que igualar isso a 2,50, que é o valor de y, ou seja, o valor do preço. Façamos isso, então, na função de demanda.

y = -7x + \frac{47}{2}

Substituir.

2,50 = - 7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

-7x  = - \frac{47}{2} + 2,50

A fração 47/2 corresponde a 23,5. É mais interessante para nós, nesse caso, utilizar o valor decimal.

-7x  = - 23,5 + 2,50

Somar logo.

-7x = -21

Podemos multiplicar por -1 para tirar os sinais negativos.

7x = 21

Passar o x dividindo

x = \frac{21}{7}

Dividir

\boxed{x = 3}

Para um preço de R$ 2,50, a quantidade demandada é de 3 unidades.



B) Basta igualar as duas formulinhas.

5x - \frac{1}{2} = -7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

5x + 7x = \frac{47}{2} + \frac{1}{2}

Somar tudo. Como as frações têm o mesmo denominador, <u>nada de </u><u>mmc</u>! Basta somar os numeradores.

12x = \frac{48}{2}

Podemos dividir lá, olha:

12x = 24

Passar o x dividindo

x = \frac{24}{12}

Dividir

\boxed{x = 2}

O ponto de equilíbrio é o valor 2.



C) Basta, então, igualar as fórmulas da oferta e da demanda a 10.

Fórmula da oferta

10 = 5x - \frac{1}{2}

Passar o que é x de um lado e o que é número do outro lado.

5x = 10 - \frac{1}{2}

Se 1/2 = 0,5, dá pra resolver sem fazer mmc:

5x = 10 - 0,5

Subtrair

5x = 9,5

Passar dividindo

x = \frac{9,5}{5}

Dividir.

\boxed{x = 1,9}

Fórmula da demanda

10 = -7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

-7x = \frac{47}{2} - 10

Divide 47/2, vai.

-7x = 23,5 - 10

Subtrair.

-7x = 13,5

Passar o 7 dividindo.

x = - \frac{13,5}{7}

Vamos dividir e transformar em decimal.

\boxed{x = -1,9285714285714285714285714285714}


Subtrair a oferta pela demanda.

x = 1,9 - (-1,9285714285714285714285714285714)

Subtrair.

\boxed{x = 3,8285714285714285714285714285714}

Arredondando, o preço será de R$ 3,83.

8 0
3 years ago
The average weight of David, Esther, and Henry is 42.6 kg. Esther is twice as heavy as Henry. David is 5.2 kilograms lighter tha
kari74 [83]

Answer:

  53.2 kg

Step-by-step explanation:

Let E represent Esther's weight. Then Henry's weight is E/2, and David's weight is E-5.2. Their average weight is ...

  ((E-5.2) + E + (E/2))/3 = 42.6

  2.5E -5.2 = 127.8 . . . . . . . . . . multiply by 3, simplify

  2.5E = 133 . . . . . . . . . . . . . . . . add 5.2

  E = 133/2.5 = 53.2 . . . . kg

Esther's weight is 53.2 kg.

7 0
4 years ago
Graph the relation and tell whether it is a function (1,3) (2,3) (-1,4) (|-1), (-3,2)
kramer

Answer:

no

Step-by-step explanation: does not pass the vertical line test

3 0
3 years ago
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