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Airida [17]
2 years ago
6

Please answer! (1) what mistake was made? (2) what suggestion could help avoid that?

Mathematics
1 answer:
AveGali [126]2 years ago
3 0

Answer:

1) the signs of the numbers is not in standard form

2) always make sure that the signs of the two equations is standarised and then solve

please follow me

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Which equation could be used to solve the problem?
castortr0y [4]
I think B

J U S T I F I C A T I O N
3 0
3 years ago
Is 3 kg equal to 6 lbs? please i nned the answer for a math exam thank you
suter [353]
It’s equal to 6.614 pounds.
6 0
2 years ago
Read 2 more answers
Please HElppppppppppppp meeeeeeee! I have less than 10 minutes!
attashe74 [19]

Answer:

A) 5  3/10

B) 785 3/20

Step-by-step explanation:

Hope this helps <3

you find a common denominator and then simplify all fractions to that common denominator. then, you add them up!

2 1/5 + 3 1/10

5 can fit into 10 twice so it becomes...

2 2/10 + 3 1/10 which equals

<u>5 3/10</u>

472 2/5 + 312 3/4

5 times 4 is 20

472 8/20 + 312 15/20

there is a remainder of 3 for the fractions so you put it over 20.

<u>785 3/20</u>

8 0
2 years ago
I need help!! This is getting a little harder than I expected
MAXImum [283]

Length of the side = 9 cm

Diagonal = 9\sqrt{2} cm

Solution:

Area of the square = 81 square centimeters

In square all sides are equal.

Area of the square = side × side

Side × side = 81

Side² = 9²    (∵81 = 9²)

Taking square root on both sides, we get

Side = 9 cm

Length of the side = 9 cm

To find the length of the diagonal:

In square all the angles are right angle.

Diagonal splits the square into two right angle triangle.

Using Pythagoras theorem,

<em>In right triangle, square of the hypotenuse is equal to the sum of the square of the other two sides.</em>

Here, diagonal is the hypotenuse.

\text{Diagonal}^2=9^2+9^2

\text{Diagonal}^2=81+81

\text{Diagonal}^2=2\times 81

Taking square root on both side,

Diagonal = 9\sqrt{2} cm

6 0
3 years ago
Radio tower had a special on rechargeable batteries. It sold AA for $1 and AAA for $0.75. It sold 42 batteries on a single day a
PIT_PIT [208]
AA = $1
AAA= $0.75

AA + AAA = 42

$1AA + $0.75AAA= $37

AA + AAA = 42
AA + AAA-AAA= 42- AAA
AA = 42- AAA

$1(42- AAA) + $0.75AAA= $37
$42 - AAA +0.75AAA = $37
$42 -0.25AAA= $37
$42-$42 -0.25AAA= $37 -$42
-0.25AAA= -5
-0.25AAA/-0.25 = -5/-0.25
AAA= 20

AA + AAA= 42
AA + 20 = 42
AA +20 -20 = 42-20
AA= 22

Check
$1AA + $0.75AAA= $37
$1(22)+ $0.75(20)= $37
$22 + $15 =$37
$37 = $37


5 0
3 years ago
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