A(n) = 2 + 9(n - 1) = 2 + 9n - 9
A(n + 1) = 2 + 9(n + 1 - 1) = 2 + 9n = (2 + 9n - 9) + 9 = A(n) + 9
Therefore, the recursive formular is A(n) = A(n - 1) + 9
Answer:
c = 5
Step-by-step explanation:
- 6 + 2c = 3c -(6+5)
-6 + 2c = 3c -11
-6 + 11 = 3c- 2c
5 = c
Answer:Your left hand side evaluates to:
m+(−1)mn+(−1)m+(−1)mnp
and your right hand side evaluates to:
m+(−1)mn+(−1)m+np
After eliminating the common terms:
m+(−1)mn from both sides, we are left with showing:
(−1)m+(−1)mnp=(−1)m+np
If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:
(−1)(−1)mn=(−1)n.
It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:
(−1)(−1)mn=(−1)−n=1(−1)n
Multiplying both sides by (−1)n then yields:
1=(−1)2n=[(−1)n]2 which is always true, no matter what n is
Answer:16.97cm
Step-by-step explanation:
To find the hypotenuse side of an isosceles of side 12cm each
Using pythagoras theorem
hyp^2=opp^2+adj^2
hyp^2=12^2+12^2
Hyp^2=144+144
hyp=√288
Hyp=16.97cm
Answer:
The digits arranged in order from least to largest is 3.011, 3.09, 3.9, 9.3
Step-by-step explanation:
The arrangement of decimals in order from smallest to largest can be done by taking note of the digit in the unit portion, the tenths, hundredths and thousandths.
The numbers are;
9.3
3.09
3.9
3.011
The largest number is the 9.3
Of the three numbers with 3 as unit, the lowest hundredths is 0.011, therefore, we have;
Therefore, the least (lowest) number = 3.011
The next is the 3.09 as 0.09 is larger than 0.011
Then the second number is 3.9
The digits arranged in order from least to largest is then 3.011, 3.09, 3.9, 9.3.
