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Trava [24]
3 years ago
9

Help! Everyone keeps trolling me!

Mathematics
1 answer:
zhenek [66]3 years ago
5 0

9514 1404 393

Answer:

  1. 0 < x < 4
  2. (- ∞ < x < 0) ∪ (4 < x < ∞)
  3. x ∈ {0, 4}

Step-by-step explanation:

1. The solution is the set of x-values for which the graph is above the x-axis, where y = 0. Those x-values are in the interval (0, 4).

__

2. The solution is the set of x-values for which the graph is below the x-axis. Those x-values are in either of the two intervals (-∞, 0) or (4, ∞).

__

3. The x-intercepts of the graph are x=0 or x=4.

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Why does it takes 3 copies of 1/6 to show the same amount as 1copy of 1 / 2
Veseljchak [2.6K]
Because 1/2 ≠ 1/6.

We know that 1/6 < 1/2, so we can set up an equation to see how many copies are needed for them to be equal.

(1/6)x = 1/2
[(1/6)x] × 6 = [1/2] × 6
x = 6/2 = 3

This equation shows that 1/6 × 3 = 1/2, therefore we need 3 copies of 1/6 to equal 1 copy of 1/2.
3 0
3 years ago
Read 2 more answers
Question is down below
Bingel [31]

This is a great question!

To determine the probability with which two sweets are not the same, you would have to subtract the probability with which two sweets are the same from 1. That would only be possible if she chose 2 liquorice sweets, 5 mint sweets and 3 humburgs -

Probability( 2 Liquorice) = 12 / 20 * 11 / 19

As you can see, the first time you were to choose a Liquorice, there would be 12 out of the 20 sweets present. After taking that out however, there would be respectively 11 Liquorice out of 19 remaining. Apply the same concept to each of the other sweets -

Probability(2 Mint ) = 5 / 20 * 4 / 19,\\Probability( 2 Humbugs ) =  3/20 * 2/19

____

Calculate the probability of drawing 2 of each, add them together and subtract from one to determine the probability that two sweets will not be the same type of sweet!

1-\left(\frac{132}{380}+\frac{20}{380}+\frac{6}{380}\right) =\\\frac{111}{190}

<u><em>Thus, the probability should be 111 / 190</em></u>

5 0
3 years ago
Consider the graph of the linear function h(x) = –6 + x. Which quadrant will the graph not go through and why?
Lesechka [4]
H ( x ) = - 6 + x
m = 1 ( the slope )
b = - 6 ( y - intercept )
x - intercept: 
0 = - 6 + x
x = 6 
The graph is going through Quadrants:  I, II and IV.
Answer:
B ) Quadrant II, because the slope is positive and y-intercept is negative.
6 0
3 years ago
Read 2 more answers
3. What is the slope of the line through the points (2, 5) and (6, 13)?
White raven [17]

Answer:

m = 2

Step-by-step explanation:

m=\frac{rise}{run}=\frac{13-5}{6-2}=\frac{8}{4}=\boxed{2}

Hope this helps.

8 0
3 years ago
If the leading coefficient of a quadratic function is negative then the graph of the function extends from?
coldgirl [10]
I wouldn't use the phrase "extends from."  If the leading coeff. is neg, then the graph opens downward.  Without more info we do not know the max of this fn.  If we did know it, we could state that the graph max is (value) and that the graph "extends downward from this value."

5 0
3 years ago
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