Can you do it step by step

Seth uses 17 linking cubes to make a model house. The model house is in the shape of a rectangle and is one cube high. How many

Masja [62]

Answer:

We conclude that Seth can make the model of the house on 9 different ways.

Step-by-step explanation:

We know that Seth uses 17 linking cubes to make a model house. The model house is in the shape of a rectangle and is one cube high.

We calculate how many different ways could Seth make the model of the house:

$C_8^9=\frac{9!}{8!(9-1)!}=9$

We conclude that Seth can make the model of the house on 9 different ways.

8 0

3 years ago

Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypot

Nina [5.8K]

Answer: a. 0.1031; fail to reject the null hypothesis

Step-by-step explanation:

Given: Significance level : $\alpha=0.05$

The test statistic in a two-tailed test is z = -1.63.

The P-value for two-tailed test : $2P(Z>|z|)=2P(Z>|-1.63|)=0.1031$ [By p-value table]

Since, 0.1031 > 0.05

i.e. p-value > $\alpha$

So, we fail to reject the null hypothesis. [When p< $\alpha$ then we reject null hypothesis ]

So, the correct option is a. 0.1031; fail to reject the null hypothesis.

8 0

3 years ago

Find the value of c that makes each trinomial a perfect square<br> x^2-19x+c<br> Please Help! :)

tensa zangetsu [6.8K]

The value of c is $\frac{361}{4}$

Explanation:

Given that the trinomial is $x^2-19x+c$

We need to determine the value of c such that the trinomial is a perfect square.

The value of c can be determined using the formula,

$c=(\frac{b}{2})^2$

From the trinomial, the value of b is given by

$b=-19$

Substituting the value of b in the above formula, we have,

$c=(\frac{-19}{2} )^2$

Squaring both the numerator and denominator, we have,

$c=\frac{361}{4}$

Thus, the value of c is $\frac{361}{4}$ which makes the trinomial a perfect square.

4 0

3 years ago

In any triangle ABC, which of the relations

MrRa [10]

ab+bc>can is the correct answer

3 0

3 years ago

In a large school, it was found that 77% of students are taking a math class, 74% of student are taking an English class, and 70

Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that $P(A) = 0.77$

74% of student are taking an English class

This means that $P(B) = 0.74$

70% of students are taking both

This means that $P(A \cap B) = 0.7$

Find the probability that a randomly selected student is taking a math class or an English class.

This is $P(A \cup B)$ , which is given by:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

So

$P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81$

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

$1 - P(A \cup B) = 1 - 0.81 = 0.19$

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

6 0

3 years ago