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Ksivusya [100]
2 years ago
7

Can someone please help me?

Mathematics
2 answers:
joja [24]2 years ago
4 0

Answer: Knowing proportional relationships help in different ways such as in constant change, multiple representations, etc.

Hope this helped.

user100 [1]2 years ago
3 0

Recognize and represent proportional relationships between quantities. Decide whether two quantities are in a proportional relationship, e.g., by testing for equivalent ratios in a table or graphing on a coordinate plane and observing whether the graph is a straight line through the origin.
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1k + 9&gt;30 <br><br> Plis ayúdenme
Leni [432]

Answer:

Step-by-step explanation:

1k +9 > 30

1k +9 -9 > 30 -9

1k > 21

k > 21

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Describe how to find all the points on a baseball field that are equidistant from second base and third base
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This might help explain how to do a very similar problem.... http://www.mathopenref.com/constbisectline.html
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3 years ago
How many people live in the state of Tennessee?
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6.549 million in 2014 i hope this helps.
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3 years ago
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A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose pe
soldier1979 [14.2K]

Using the normal distribution, it is found that:

a) 0.8599 = 85.99% probability that x is more than 60.

b) 0.1788 = 17.88% probability that x is less than 110.

c) 0.6811 = 68.11% probability that x is between 60 and 110.

d) 0.0643 = 6.43% probability that x is greater than 125.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of 87, thus \mu = 87.
  • The standard deviation is of 25, thus \sigma = 25.

Item a:

This probability is <u>1 subtracted by the p-value of Z when X = 60</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 87}{25}

Z = -1.08

Z = -1.08 has a p-value of 0.1401.

1 - 0.1401 = 0.8599

0.8599 = 85.99% probability that x is more than 60.

Item b:

This probability is the <u>p-value of Z when X = 110</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 87}{25}

Z = 0.92

Z = 0.92 has a p-value of 0.8212.

1 - 0.8212 = 0.1788.

0.1788 = 17.88% probability that x is less than 110.

Item c:

This probability is the <u>p-value of Z when X = 110 subtracted by the p-value of Z when X = 60</u>.

From the previous two items, 0.8212 - 0.1401 = 0.6811.

0.6811 = 68.11% probability that x is between 60 and 110.

Item d:

This probability is <u>1 subtracted by the p-value of Z when X = 125</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{125 - 87}{25}

Z = 1.52

Z = 1.52 has a p-value of 0.9357.

1 - 0.9357 = 0.0643.

0.0643 = 6.43% probability that x is greater than 125.

A similar problem is given at brainly.com/question/24863330

7 0
3 years ago
A certain star is 2.6×102 light years from the Earth. One light year is about 5.9×1012 miles. How far from the earth​ (in miles)
navik [9.2K]

Answer:

2.5 x 10^{15} miles

3 0
2 years ago
Read 2 more answers
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