What is the equation, in slope-intercept form, of the line that is perpendicular to the line y – 4 = –2/3 (x – 6) and passes thr

Question

Maru [420]

3 years ago

14

What is the equation, in slope-intercept form, of the line that is perpendicular to the line y – 4 = –2/3 (x – 6) and passes thr

ough the point (−2, −2)?
a. y = –x –
b. y = –x +
c. y = x – 1
d. y = x + 1

Mathematics

1 answer:

Gre4nikov [31] · Answer 1 · 2022-06-15T06:23:16+03:00

Gre4nikov [31]3 years ago

4 0

Y-4=-2/3(x-6)
(y-(-2))=(-3/2)(x-(-2))
(y+2)=(-3/2)(x+2)
y-4=(-2/3)x+4
y=(-2/3)x+8
y+2=(-3/2)x-3
y=(-3/2)x-5
m2=(-3/2), (-2,-2)
y=(-3/2)x+b
(-2)=(-3/2)(-2)+b
-2=-3+b
1=b
d.) y=x+1, as the y-intercept is positive