Answer:
9 and 18
Step-by-step explanation:
The surface area of a cone is equal to the base plus the lateral area.
The base is a circle, and has a diameter of 16 meters.
The radius is always half the diameter, so it is 8 meters.
The area of a circle = πr², where r is the radius. π(8)² = 64π ≈ 201.06193
The area of the base is ≈ 201.06193.
To find the lateral area of the cone, we need to find the slant height.
Since the height, radius, and slant height of the cone form a right triangle, we can use the Pythagorean Theorem to find the slant height with what we are given.
radius² + height² = slant height²
8² + 37² = slant height²
64 + 1369 = slant height²
1433 = slant height²
slant height = √1433
The lateral area of a cone is equal to πrl, where r = radius and l = slant height.
πrl = π(8)(√1433) ≈ 951.39958
(there are other formulas which do the same thing, but it doesn't matter.)
Now we add the lateral area and base together to find our surface area.
201.06193 + 951.39958 = 1152.46151 which rounds to C. 1,152 m².
If you are using a calculator, simply enter 78÷260×100 which will give you 30 as the answer.
Answer:
Please check the explanation
Step-by-step explanation:
Given the function
Given that the output = -3
i.e. y = -3
now substituting the value y=-3 and solve for x to determine the input 'x'
switch sides
Add 1 to both sides
![\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}](https://tex.z-dn.net/?f=%5Cmathrm%7BFor%5C%3A%7Dg%5E3%5Cleft%28x%5Cright%29%3Df%5Cleft%28a%5Cright%29%5Cmathrm%7B%5C%3Athe%5C%3Asolutions%5C%3Aare%5C%3A%7Dg%5Cleft%28x%5Cright%29%3D%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%2C%5C%3A%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%5Cfrac%7B-1-%5Csqrt%7B3%7Di%7D%7B2%7D%2C%5C%3A%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%5Cfrac%7B-1%2B%5Csqrt%7B3%7Di%7D%7B2%7D)
Thus, the input values are:
![x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}](https://tex.z-dn.net/?f=x%3D-%5Csqrt%5B3%5D%7B2%7D%2B5%2C%5C%3Ax%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B2%7D%5Cleft%281%2B5%5Ccdot%20%5C%3A2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cright%29%7D%7B2%7D-i%5Cfrac%7B%5Csqrt%5B3%5D%7B2%7D%5Csqrt%7B3%7D%7D%7B2%7D%2C%5C%3Ax%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B2%7D%5Cleft%281%2B5%5Ccdot%20%5C%3A2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cright%29%7D%7B2%7D%2Bi%5Cfrac%7B%5Csqrt%5B3%5D%7B2%7D%5Csqrt%7B3%7D%7D%7B2%7D)
And the real input is:
![x=-\sqrt[3]{2}+5](https://tex.z-dn.net/?f=x%3D-%5Csqrt%5B3%5D%7B2%7D%2B5)
Answer:
60 mph
Step-by-step explanation:
We don't know how far Jimmy drives in each direction. Let this distance be d. Then, d = rate * time, and d = r(2 hours) (where r represents his speed while driving to the ferry).
But it's also true that d = (r - 20 mph)(3 hours).
Equating d = r(2 hours) and d = (r - 20 mph)(3 hours), we get:
r(2) = (r - 20)(3), or 2r = 3r - 60.
Subtracting 2r from both sides yields 0 = r - 60, so that r = 60 mph.
Jimmy averaged 60 mph on the outbound trip.
